Answer:
Copper ions are reduced into copper atoms.
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
Explanation:
During electrolysis, the positive H⁺ and Cu⁺ ions move to the negative cathode and negative OH⁻ and Cl⁻ ions move to the positive anode.
At cathode, copper ions are preferentially discharged due to the low electromotive force required to discharge them compared to the hydrogen ion. The copper ions gain the two electrons lost by the chloride ions when the are discharged. (2 Cl⁻₍aq₎ → Cl₂₍g₎ + 2e⁻)
Thus the half equation is as follows:
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
Answer:
ph = 4.73
Explanation:
Determine the pH of a 0.62 M NH4NO3 solution at 25C
The Kb for NH3 is 1.76 x 10^-5
NH4+ is the conjugate acid of the base NH3
Ka for NH4+ = K water / K NH3 conjugate base
Ka = 1 × 10⁻¹⁴ / 1.76 10⁻⁵
= 5.68 × 10⁻¹⁰
which is he Ka for
NH4 + H2O --> NH4OH + H⁺
Ka = [NH4OH] [H+] / [NH4)+]
5.68 × 10⁻¹⁰ = [X] [X] / [0.62]
X² = 3.52 × 10⁻¹⁰
X = [H+] = 1.88 × 10⁻⁵
p of that H+ = 4.73
ph = 4.73
<span>STP means standard temperature
and pressure at 0°C (273K) and 1 atm (atmosphere). The density of the unknown
gas is 0.63 gram per liter. The deal gas equation is PV = nRT. The n is the
numer of moles and can be represented as mass of the gas, m, divided by the
molar mass, c. so we have,</span>
PV = nRT
PV = (m/c)RT
Since the density is d = m/V
Pc = (m/V)RT
Pc = dRT
c = drT/P
substitute the values into the equation,
c = [(0.63g/L)(0.08206
L-atm/mol-K)(273K)]/(1atm)
<u>c = 14.11 g/mol</u>
Answer:
Just 4...
Explanation:
There are 2 hydrogen atoms in 1 water molecule, so in 2 water molecules would have 4 hydrogen atoms.
*booyah*