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Soloha48 [4]
3 years ago
15

A liquid has a density of 1.17 g/cm3, how many liters of the liquid have a mass of 3.75 kg

Chemistry
1 answer:
Luda [366]3 years ago
5 0
<span>There are 1000 cm3 in 1 liters. Hence 1 liter of the liquid would weigh: 1000 cm3 x (1.17 g/cm3) = 1170 gm and there are 1000 gm in 1 kg, so we want enough liters to have a mass of 3.75 kg x 1000 gm/kg = 3750 gm Hence, # of liters = desired mass / # of gm per liter = 3750 gm / 1170 gm/liter = 3.2051282 liters</span>
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Question 6: Iron metal and chlorine gas react to form iron (III) chloride: 2 Fe(s) + 3 Cl2 (g) → 2 FeCl3 (s)
Bas_tet [7]

10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

What ois Theoretical yield ?

The quantity of a product obtained from a reaction is expressed in terms of the yield of the reaction.

The amount of product predicted by stoichiometry is called the theoretical yield, whereas the amount obtained actually is called the actual yield.

  • As 2 moles (111.68 g) of Fe consumes 213 gm of Cl₂ to produce 2FeCl₃

Therefore ,

10 gm of Fe will consumes = 213 / 111.68 x 10 = 19 gm Cl₂

  • As 2 moles (111.68 g) of Fe produces 2 mole (324 gm) of FeCl₃

Therefore ,

10 gm of Fe will produces = 324 / 111.68 x 10 = 29 gm FeCl₃

Hence , 10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

Learn more about Theoretical yield here ;

brainly.com/question/12704041

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4 0
2 years ago
How many moles are in 28g of Fe2O3
nlexa [21]

Find the molar mass of Fe_2O_3

2Fe = 2*56 = 112

3O = 3* 16 =    48

Molar Mass = 160 grams

moles= given mass / molar mass

moles = 28 / 160

moles = 0.175   <<<< answer

6 0
3 years ago
alculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer. Express your answer using two decima
svetlana [45]

A 1.0-L buffer solution contains 0.100 mol  HC2H3O2 and 0.100 mol  NaC2H3O2. The value of Ka for HC2H3O2 is 1.8×10−5.

Calculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer.

Answer:

The pH of this solution = 5.06  

Explanation:

Given that:

number of moles of CH3COOH = 0.100 mol

volume of the buffer solution = 1.0 L

number of moles of NaC2H3O2 = 0.100 mol

The objective is to Calculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer.

we know that concentration in mole = Molarity/volume

Then concentration of [CH3COOH] = \mathtt{ \dfrac{0.100  \ mol}{ 1.0  \  L }}  = 0.10 M

The chemical equation for this reaction is :

\mathtt{CH_3COOH + OH^- \to CH_3COO^- + H_2O}

The conjugate base is CH3COO⁻

The concentration of the conjugate base [CH3COO⁻] is  = \mathtt{ \dfrac{0.100  \ mol}{ 1.0  \  L }}  

= 0.10 M

where the pka (acid dissociation constant)for CH3COOH = 4.74

If 0.035 mol of NaOH is added  to the original buffer, the concentration of NaOH added will be = \mathtt{ \dfrac{0.035  \ mol}{ 1.0  \  L }} = 0.035 M

The ICE Table for the above reaction can be constructed as follows:

                  \mathtt{CH_3COOH \ \ \   +  \ \ \ \ OH^-  \ \ \to \ \ CH_3COO^-  \ \ \ + \ \ \  H_2O}

Initial             0.10               0.035         0.10                  -

Change        -0.035          -0.035       + 0.035              -

Equilibrium    0.065              0              0.135               -

By using  Henderson-Hasselbalch equation:

The pH of this solution = pKa + log \mathtt{\dfrac{CH_3COO^-}{CH_3COOH}}

The pH of this solution = 4.74 + log \mathtt{\dfrac{0.135}{0.065}}

The pH of this solution = 4.74 + log (2.076923077 )

The pH of this solution = 4.74 + 0.3174

The pH of this solution = 5.0574

The pH of this solution = 5.06    to two decimal places

7 0
3 years ago
Think about the different rules that describe how gases behave. To do this, refer to what you have learned about the two princip
VMariaS [17]

Answer:

Described down below.

Explanation:

Hello,

- Boyle's law: correlation between pressure and volume (assuming temperature and amount of gas remain constant). One common use of Boyle’s law is to predict the new volume of a gas when the pressure is changed (at constant temperature), or vice versa

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- Avogadro's law: correlation between amount of gas and volume (assuming temperature  and pressure p remain constant). As an example, since we can blow up a basketball, we are adding more gas molecules into it. The more gaseous molecules, the greater the volume.

- Dalton's law: correlation that states that for a mixture of gases in a container, the total pressure exerted is the addition among each pressure that each gas would exert if it were alone. It is useful to analyze the effects of which partial pressure might have on scuba divers. While the total gas pressure increases as a diver increases their descent, the partial pressure of each gas involved increases as well which might cause harm to the diver’s body if proper actions are not carried out.

- Gay-Lussac's law: it states that when the temperature of a sample of gas in a rigid container is increased, the pressure of the gas increases as well. An interesting example is shown when gun pin strikes, because it ignites the gun powder and this increases the temperature which in turn increases the pressure and bullet is fired from the gun.

Best regards.

4 0
4 years ago
The particles that make up matter do not change during a ?
Bogdan [553]
Matter can only me transformed, but not created or destroyed.
8 0
4 years ago
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