X over 90 is equal to 60 over 100, cross multiply, you'll get 60*90 and 100x. 60*90 is 5400. Divide that by 100, and you get 54.
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
Answer:
option D
Step-by-step explanation:
Recursive rule: Next term is obtained by multiplying (1/3) wiht the previous term
Answer:
There are 6 ways to run 10 m between two cones of the four cones giving a maximum available distance to run as 60 meters
Step-by-step explanation:
The parameters given are
Distance between two cones = 10 m
Number of cones = 4
Therefore, number of ways to choose two 10 m distances (distance between two cones) from the four cones = 
= 6
Hence there are only six 10 m distances to run between two cones which gives a maximum distance available to run as 60 m.
Answer:
B
Step-by-step explanation:
