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son4ous [18]
2 years ago
14

Explain briefly how you would obtain crystals of sodium chloride from a mixture of sodium chloride ,lead[ii]oxide and iron filin

gs
Chemistry
1 answer:
Arisa [49]2 years ago
6 0

Answer:

See explanation

Explanation:

All the substances in the mixture; sodium chloride ,lead II oxide and iron filings are solids.

The first step is to use a magnet to separate the iron fillings which is a magnetizable material.

The remaining part of the mixture is now dissolved in water. Lead II oxide is insoluble in water while sodium chloride is very soluble in water hence a filtrate and a residue are obtained.

The residue is lead II oxide which can be dried to recover the solid. The filtrate contains sodium chloride which is recovered by evaporating the solution to dryness.

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What is the octet rule?
PolarNik [594]

The Octet rule is a general rule of thumb that applies to most atoms. Basically, it states that every atom wants to have eight valence electrons in its outermost electron shell.


4 0
3 years ago
Read 2 more answers
The equilibrium constant for the gas-phase isomerization of borneol (c10h17oh) to isoborneol at 503 k is 0.106. a mixture consis
Dimas [21]
The solution is as follows:

K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106

The molar mass of isoborneol/borneol is 154.25 g/mol

Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol

Use the ICE approach

        borneol  →  isoborneol
I         0.0972           0.0486
C         -x                     +x
E     0.0972 - x        0.0486 + x

Total moles = 0.1458

Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P

0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832 

Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
6 0
3 years ago
1 Calcium carbonate breaks down on heating to produce calcium oxide and carbon dioxide gas.
Alborosie

Answer:  See below

Explanation:

1.  a)  0.15 moles calcium carbonate  (15g/100g/mole)

   b)  0.15 moles CaO  (molar ratio of CaO to CaCO3 is 1:1)

   c)   8.4 grams CaO  (0.15 moles)*(56 grams/mole)

2. a)  0.274 moles Na2O  (17g/62 grams/mole)

   b)  46.6 grams NaNO3  (2 moles NaNO3/1 mole Na2O)*(0.274 moles Na2O)*(85 g/mole NaNO3)

7 0
2 years ago
In terms of bonds what would the molecule C6H12 be classified as
docker41 [41]

It has a double C=C bond so that means it's unsaturated, but it can also be a cyclic compound with only simple C-C bonds

5 0
2 years ago
The balanced redox reactions for the sequential reduction of vanadium are given below.
Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)

2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)

On adding above equations, we get the following combined equation.

2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn

We need 0.0392 grams of Zn metal to completely reduce vanadium.

6 0
2 years ago
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