Answer: Im not sure if you are doing this in your class.
Explanation:
So... for the element of MAGNESIUM, you already know that the atomic number tells you the number of electrons. That means there are 12 electrons in a magnesium atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and two more in shell three
K₃PO₄<span>(aq) reacts with Al(NO</span>₃)₃(aq) and form AlPO₄(s) and KNO₃(aq) as the products.
Before writing net ionic reaction, following steps should be followed.
Step 1 : Write the balanced chemical equation for the reaction and indicate the state of compound as aq,s,g or l.
K₃PO₄(aq) + Al(NO₃)₃(aq) → AlPO₄(s) + 3KNO₃(aq)
Step 2 : Identify the ionic species which dissolve in water to form ions.
K₃PO₄(aq) → 3K⁺(aq) + PO₄⁻(aq)
Al(NO₃)₃(aq) → Al³⁺(aq) + 3NO₃⁻(aq)
KNO₃(aq) → K⁺(aq) + NO₃⁻(aq)
Step 3 : Write the equation again by using ions.
3K⁺(aq) + PO₄⁻(aq) + Al³⁺(aq) + 3NO₃⁻(aq) → AlPO₄(s) +3K⁺(aq) + 3NO₃⁻(aq)
Step 4 : Identify the similar species in both side of the equation and cut off them.
3K⁺(aq) and 3NO₃⁻(aq) present in both sides. Hence, those ions can be cut off.
Step 5 : Get the final ionic equation.
The net ionic equation for the given reaction is
Al³⁺(aq) + PO₄⁻(aq) → AlPO₄(s)
Yo sup??
the answer is option A ie
96.056 grams/mole
because mass of S is 32 gm and mass of O is 16 gm
Hope this helps
Answer:
Option B
Explanation:
Avagadro's hypothesis showed that at constant temperature and pressure equal volume of all gases contains equal no of molecules.
Avagadro's constant is known as 6.022×10^23
Approx.
15
⋅
g
of metal.
Explanation:
Moles of iron oxide,
F
e
2
O
3
=
21.6
⋅
g
159.69
⋅
g
⋅
m
o
l
=
0.135
⋅
m
o
l
with respect to the oxide.
But by the composition of the oxide, there are thus
2
×
0.135
⋅
m
o
l
×
55.8
⋅
g
⋅
m
o
l
−
1
iron metal
=
?
?
g
.
An extraordinary percentage of our budgets goes into rust prevention;
iron(III) oxide
is only part of the redox chemistry. Once you put up a bridge or a skyscraper, which is inevitably steel-based structure, it will begin to corrode.
