








☯ <u>Using 1st equation of motion </u>











☯ <u>Now, Finding the force exerted </u>






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☯ <u>Hence</u>, 

Answer:
Initial pressure = 6 atm. Work = 0.144 J
Explanation:
You need to know the equation P1*V1=P2*V2, where P1 is the initial pressure, V1 is the initial volume, and P2 and V2 are the final pressure and volume respectively. So you can rearrange the terms and find that (1.2*0.05)/(0.01) = initial pressure = 6 atm. The work done by the system can be obtained calculating the are under the curve, so it is 0.144J
Answer:
ya we can write the imaginary character's name .
So that we can identify these imaginary people, as we cannot simply write the conversation and leave it .
Or maybe sometimes the reader will get confused as there is no name for the two people .
So, i suggest that you should write the names
Explanation:
You can even ask to your class teacher for further clarification
At a distance r from a charge e on a particle of mass m the electric field value is 8.9876 × 10⁹ N·m²/C². Divide the magnitude of the charge by the square of the distance of the charge from the point. Multiply the value from step 1 with Coulomb's constant.
<h3>what is magnitude ?</h3>
Magnitude can be defined as the maximum extent of size and the direction of an object.
It is used as a common factor in vector and scalar quantities, as we know scalar quantities are those quantities that have magnitude only and vector quantities are those quantities have both magnitude and direction.
There are different ways where magnitude is used Magnitude of earthquake, charge on an electron, force, displacement, Magnitude of gravitational force
For more details regarding magnitude, visit
brainly.com/question/28242822
#SPJ1
Answer:
The value of third charge is 0.8μC.
Explanation:
Given that.
Magnitude of net force=4.444 N
According to figure,
Suppose, First charge = 2.4 μC
Second charge = 6.2 μC
Distance r₁ = 9.8 cm
Distance r₂ = 2.1 cm
We need to calculate the value of r
Using Pythagorean theorem

Put the value into the formula


We need to calculate the force
Using formula of force

Force F₁₂,



Force F₂₃,

We need to calculate the value of third charge





Hence, The value of third charge is 0.8μC.