Answer:
The correct answer is
e. NH3(aq) + H+(aq) --> NH4+(aq)
Explanation:
To solve this, we write out the indidual ionization reation for aqueous ammonia and nitric acid thus
For aqueous ammonia we have
NH₃(aq) + H₂O(l) ↔ NH₄⁺(aq) + OH⁻(aq)
Aqueous ammonia is a weak base and therefore undergoes partial ionization hence the reversible reaction sign
As the level of ionization will not be more than 5% OH⁻ cannot represebt the weak base
For nitric acid we have
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
a strong acid like nitric acid undergoes conplete ionization in the solution
The total equation is NH₃(aq) + HNO₃(aq) → NH₄NO₃(aq)
The sum of the ionic equation is
NH₃(aq) + H⁺(aq) + NO₃⁻(aq) → NH₄⁺(aq) + NO₃⁻(aq)
The ionic equation is
NH₃(aq) + H⁺(aq) → NH₄⁺(aq)
Answer:
Magnesium, Mgstart text, M, g, end text, is a group 2 element that will form 2+ cations. Because it usually forms cations of only one type, we don't need to specify its charge. We can simply refer to the cation in the ionic compound as magnesium. ... Therefore, the name for the compound is magnesium phosphide.
Explanation:
(this may or not be correct)
-also i finished that drawing you wanted :p-
Answer:
Piso = 32.17 Torr
Pprop = 5.079 Torr
yprop = 0.1364
yiso = 0.8636
Explanation:
From the question; we can opine that :
- The mole fraction of isopropanol in a mixture of isopropanol and propanol will be 1.
-
The partial pressure of isopropanol will be its mole fraction multiplied by vapor pressure of isopropanol
-
The partial pressure of propanol will be its mole fraction multiplied by vapor pressure of propanol
-
In the vapor, the mole fraction of propanol will be its partial pressure divided by the sum of the two partial pressures
NOW;
When xprop = 0.243; xisopropanol will be 1- 0.243 = 0.757
P°iso = 45.2 Torr at 25 °C so
Piso will be 45.2 × 0.757 = 32.17 Torr
Pprop will be 20.9 × 0.243 = 5.079 Torr
yprop = 5.079/(5.079 +32.17) = 0.1364
yiso = 1-0.1364 = 0.8636
Answer:
the answer is A
Explanation:
since during a cold front the cold air replaces the warm air
