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iragen [17]
2 years ago
8

Is the Transco Tower were actually 3000 meters tall how long would an object take to free fall off the top of the building

Physics
1 answer:
jeka57 [31]2 years ago
4 0

Answer:

S = V0 t + 1/2 g t^2

3000 m = 1/2 * 9.8 * t^2       initial speed is zero

t = (6000 / 9.8) ^1/2 = 24.7 sec

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Which of the following statements best explains why elements in the same family of the periodic table have similar bonding prope
slava [35]

Answer: D. The elements have the same number of valence electrons

Explanation: The chemical reactivity of elements is governed by the valence electrons present in the element.

The elements present in the same group or vertical column have similar valence configurations and thus behave similarly in chemical reactions or have similar bonding properties.

For Example: Both fluorine and chlorine belong to same family or group and both have 7 electrons in their valence shell and thus accept single electron to attain noble gas configuration.

F:9:1s^22s^22p^5

F^-:10: 1s^22s^22p^6

Cl:17:1s^22s^22p^63s^23p^5

Cl^-:18:1s^22s^22p^63s^23p^6

thus both would bond with a cation bearing a single positive charge.

3 0
3 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
Sophie [7]

Answer:

a. Wavelength = λ = 20 cm

b. Next distance of maximum intensity will be 40 cm

Explanation:

a. The distance between the two speakers is 20cm. SInce the intensity is maximum which refers that we have constructive interference and the phase difference must be an even multiple of π and equivalent path difference is nλ.

Now when distance increases upto 30 cm between the speakers, the sound intensity becomes zero which means that there is destructive interference and equivalent path is now increased from nλ to nλ + λ/2.

This we get the equation:

(nλ + λ/2) - nλ = 30-20

λ/2 = 10

λ = 20 cm

b. at what distance, sound intensity will be maximum again.

For next point calculation for maximum sound intensity, the path difference must be increased (n+1) λ. The distance must increase by λ/2 from the point of zero intensity.

= 30 + λ/2

= 30 + 20/2

=30+10

=40 cm

7 0
3 years ago
An object's describes it's distance and direction from a reference point .
Ainat [17]

6: velocity i hpe this is what your looking for

4 0
3 years ago
Read 2 more answers
Using the picture below, what is the displacement of the triangle?
zavuch27 [327]

Answer:

i think it is 40 kilometers in the positive direction... if not im sorry

Explanation:

7 0
3 years ago
The radar system of a navy cruiser transmits at a wavelength of 1.4 cm, from a circular antenna with a diameter of 2.7 m. At a r
Goshia [24]

Answer:

Distance will be 49.34 m

Explanation:

We have given wavelength \lambda =1.4cm =0.014m

Diameter of the antenna d = 2.7 m

Range L = 7.8 km = 7800 m

We have to find the smallest distance hat two speedboats can be from each other and still be resolved as two separate objects D

We know that distance is given by D=\frac{L1.22\lambda }{d}=\frac{7800\times 1.22\times 0.014}{2.7}=49.3422m

So distance D will be 49.34 m

4 0
3 years ago
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