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Dmitry_Shevchenko [17]
4 years ago
7

1.)State which definition of power below is correct.

Physics
1 answer:
Natalija [7]4 years ago
6 0

C

kW, watts, kilowatts, W

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(1) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy so
malfutka [58]

Solution :

The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :

F = ma

F = qvB and $a=\frac{v^2}{r}$

Substituting these values in the second law of Newton,

$qvB=\frac{mv^2}{r}$

Now solving for B, we get:

$B = \frac{mv}{rq}$

  $=\frac{(1.67 \times 10^{-27})(5 \times 10^{7})}{2\times 1.6 \times 10^{-19}}$

 = 0.261 T

The field strength can be obtained by using the technology of today.

7 0
3 years ago
The temperature coefficient of a certain conducting material is 5.74 × 10-3 (°C)-1. (a) At what temperature would the resistance
Alex777 [14]

Answer:

Temperature at which the resistance is twice the resistance at 20^{\circ}C is 194.216^{\circ}C

Solution:

As per the question:

Temperature coefficient, \alpha = 5.74\times 10^{- 3}^{\circ}C

Reference temperature, T_{o} = 20^{\circ}C

Resistance, R_{t} = 2R_{o}

Now, using the formula:

R_{t} = R_{o}(1 + \alpha \Delta T)

2R_{o} = R_{o}(1 + \alpha \times (T _ T_{o}))

2 = 1 + 5.74\times 10^{- 3}\times (T - 20^{\circ})

\frac{1}{5.74\times 10^{- 3}} = T - 20^{\circ}

T = 174.216 + 20 = 194.216^{\circ}

  • Yes, this temperature holds for all all the conductors of copper, irrespective of the size and shape of the conductor.

5 0
3 years ago
How did the temperature structure of the solar nebula determine planetary composition?
STALIN [3.7K]

Explanation:

The temperature of the solar nebula was decreasing as it moved away from its center. Therefore, only heavy elements could condense in the inner solar system and terrestrial planets could not form with light elements, such as gases. In the outer solar system, the Jovian planets formed mostly with gases, since temperatures were too low to allow rocky compositions.

3 0
3 years ago
The center of mass of a 1600 kg car is midway between the wheels and 0.7 m above the ground. The wheels are 2.6 m apart. (a) Wha
user100 [1]

Answer:

Explanation:

I guess we are ASSUMING that this is a rear wheel drive car as a front wheel drive car will never get the front wheel normal force to zero

If we consider it as a statics problem and choose our moment center carefully...say 0.7 m above the rear wheel to ground contact point.

Call the traction force at the rear wheels F

The normal force on the front wheels will be zero, so no moment generated by the front wheels.

Summing moments about our chosen point to zero

1600(9.8)[2.6 / 2] - F[0.7] = 0

F = 291,200

this force will create an acceleration of

a = F/m

a = 291200/1600

a = 182 m/s²

which is about 18.6 times gravity acceleration

3 0
3 years ago
A motorboat and a pwc are approaching head-on. what action should be taken?
SashulF [63]
In this situation, both of the vehicles turn towards starboard.

By turning to the starboard, or right, side, the vehicles are able to avoid collision. Because waterways are not marked in a manner like roads are, it is necessary to place such conventions of turning in situations where vehicles approach one another head on. If a convention was not in place, the risk of collision would be many times greater. For example, the motorboat operator may turn left, while the PWC operator turns right, resulting in a collision.
7 0
4 years ago
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