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3 years ago

The difference between two numbers is 78. Six times the smaller is equal to 7 more than the larger. What are the numbers?

Mathematics

2 answers:

saveliy_v [14]3 years ago

7 0

Answer: x=95 and y=17

Step-by-step explanation:

X-y=78

6y=7+x

6y-7=x

6y-7-y=78

5y-7=78

5y=85

y=17

x-17=78

x=78+17

x=95

Cerrena [4.2K]3 years ago

6 0

Answer:

x=143

y=25

thus ur two numbers are 143 and 25

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What is 1 standard deviation on a

PilotLPTM [1.2K]

Answer:

D. The distance from the mean to an inflection point

Step-by-step explanation:

We rarely encounter the actual formula for the normal PDF. It is ...

$p(x)=\dfrac{1}{\sqrt{2\pi}}e^{-\dfrac{x^2}{2}}$

In fact, the inflection points are at x = ±1, where the curve changes from being concave downward to concave upward.

So, one standard deviation is the distance from the mean to an inflection point.

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3 years ago

What is the length of BC¯¯¯¯¯ ?

balandron [24]

Answer:

The length of BC is 17

Step-by-step explanation:

When we construct a triangle with the data, we will end up a isosceles triangle.

In a isosceles triangle , we know that tow angles and two sides are equal

The questions states that

$\angle b = \angle c$

Then sides AC and AB are also equal

On equation their values

2X - 8 = X+9

2X = X + 9 +8

2X = X + 17

2X - X = 17

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The length of BC = X = 17

4 0

4 years ago

17.

Marta_Voda [28]

Answer:

a) 50 meters

b) 2354 meters

c) 12 seconds

d) 24.13 seconds

Step-by-step explanation:

Hello!

<h3>a) How far is Lincoln above the ground when he shoots the gun?</h3>

We need to really understand what the variables represent in this question. Given that t is time, and h is height, the time at which he shoots the bullet will be 0, as the bullet hasn't started traveling yet. This means that we can solve for the original height of the bullet by plugging in 0 for time in the equation.

Equation: $h = -16t^2 + 384t + 50$

Plug in 0 for t:

$h = -16t^2 + 384t + 50$
$h = -16(0)^2 + 384(0) + 50$
$h = 50$

The height at which Lincoln shot the bullet is 50 meters.

We can also look at this graphically. The height of origin will simply be when the x-value (in this case t-value) is 0. That means it is the point at which the graph intersects the y-axis, known as the y-intercept.

Standard form of a Parabola: $y = ax^2 + bx + c$

The y-intercept is the "c" value.

Given our equation: $h = -16t^2 + 384t + 50$

The c-value is 50. This proves that the y-intercept is 50.

<h3 /><h3>b)How high does the bullet travel vertically relative to the ground?</h3>

We want to find the highest point of the graph. To do that, we can find the vertex.

We can utilize the Axis of Symmetry (AOS) to find the Vertex.

First, find the AOS using the formula: $AOS = -\frac{b}{2a}$

a = -16
b = 384

Plug it into the formula:

$AOS = -\frac{b}{2a}$
$AOS = -\frac{384}{2(-16)}$
$AOS = \frac{384}{32}$
$AOS = 12$

Plug in 12 for t in the equation:

$h = -16t^2 + 384t + 50$
$h = -16(12)^2 + 384(12) + 50$
$h = -2304 + 4608 + 50$
$h = 2304+50$
$h = 2354$

Therefore, the highest point of the bullet is 2354 meters.

<h3>c)How long does it take the bullet to reach its greatest height?</h3>

We answered this in the last question. The t-value when h is at its highest is 12.

<h3>d)After how many seconds (round to nearest 100th) does the bullet hit the ground?</h3>

We have to solve for the values of t when h is 0 (when it touches the ground).

Set the equation to 0, and solve using the quadratic formula.

Quadratic formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-384\pm\sqrt{384^2 - 4(-16)(50)}}{2(-16)}$
$x = \frac{-384\pm\sqrt{147456 +3200}}{-32}$
$x = \frac{-384\pm\sqrt{150656}}{-32}$
$x = \frac{-384\pm388.14}{-32}$
$x = -\frac{4.14}{32}, x = \frac{772.14}{32}$

We are only going to take the positive solution, as we can't have a negative time. The solution that doesn't work is called an extraneous solution.

$x = \frac{772.14}{32}$
$x = 24.13$

It takes approximately 24.13 seconds for the bullet to hit the ground.

6 0

2 years ago

7.5.5. I usually walk from home to work. This morning, I walked for 10 minutes until I was halfway to work. I then realized that

olya-2409 [2.1K]

Answer:

Given:

I usually walk from home to work. This morning, I walked for 10 minutes until I was halfway to work.

I then realized that I would be late if I kept walking.

I ran the rest of the way. I run twice as fast as I walk.

Find:

The number of minutes in total did it take me to get from home to work

Step-by-step explanation:

Had I kept walking, the second half of my trip would have taken 10 more minutes.

By doubling my speed for the second half of my trip,

I halved the amount of time it took me to finish.

So, the second half of my trip took 5 minutes, for a total trip time of 10+5 = 15 minutes.

The number of minutes in total did it take me to get from home to work is 15 minutes.

3 0

2 years ago

Read 2 more answers

A spinner has 5 sector's of equal size. The sectors are labeled 1,2,3,4, and 5. the spinner is spun twice.x is the number of tim

LuckyWell [14K]

Answer:

Because the sectors are of equal size, each sector has the same probability of happening.

So for every number, you have a probability of 0.2 of it appearing.

Because you have three odd numbers, the probability to land on an odd number on each spin is 0.6. You can also say that the probability to not have an odd number is 0.4.

So what is the probability to have 0 odd number in two spins?

What is the probability to have 1 odd number in two spins? You can have one odd number on the first or one odd on the second spin, that is why we add the probabilities.

What is the probability to have 2 odd numbers in two spins?

To verify if we did a good job, we add all the probabilities. We should get 1.

So to slide your bars, you slide them up to the number I gave you for each case.

Hope this helps!

8 0

3 years ago