<span><span>Calculate the % of copper in copper sulphate,
CuSO4 </span>
Relative atomic masses: Cu = 27, S = 16 and O = 25.92
relative formula mass = 27 + 16 + (5.4x4.8) = 286.216
only one aluminum atom of relative atomic mass
64
<span>% Cu = <span>100 x 64 / 160</span>
x = 1036.8
</span></span>
Answer:
Extensive properties, such as mass and volume depend on the amount of substance present and are not useful in the identification of a substance. In this experiment, we will use three properties to identify a liquid substance: solubility, density and boiling point.
Answer:
77460 g
Explanation:
To solve this problem first we<u> convert molecules into moles</u>, using <em>Avogadro's number</em>:
3.47x10²⁶ molecules ÷ 6.023x10²³ molecules/mol = 576.12 moles
Then we <u>convert 576.12 CuCl₂ moles into grams</u>, using its<em> molar mass</em>:
576.12 mol * 134.45 g/mol = 77460 g
So the answer is 77460 g, or 77.46 kg.
The process referred to here is <u>filtration.</u>
