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GarryVolchara [31]
3 years ago
8

Ellen drove 357.9 miles. Her car gets about 21 miles per gallon. Which is the best estimate of how many gallons of gas Ellen use

d?
Mathematics
2 answers:
olga55 [171]3 years ago
7 0
The best thing to do is to divide the amount she has driven (357.9) by the miles (21)
As you're looking for an estimate, you have to round them.
357.9 rounds to 360
21 rounds to 20
Therefore, you've got to divide them
360/20= 18
Therefore, Ellen has driven approximately 18 miles
Hope this helps :)
Ann [662]3 years ago
6 0

When looking for an estimate, you have to round your numbers 21 rounded would become 20 and 357.9 would become 360. So next you would divide the numbers.

360 ÷ 20 =  18

So, Ellen would have used approximately 18 gallons of gas.

Hope this helps you. :-) 

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Mario claims that if the dinominator of a fraction is a prime number, then its decimal form is a repeting decimal. Do you agree?
vodomira [7]

Answer:

I do not agree because Mario's claim is not general.

Step-by-step explanation:

Prime numbers: These are a set of numbers that are divisible by 1 and itself only. Examples are: 2, 3, 5, 7. 11 etc.

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Considering the following fractions whose denominators are prime numbers:

\frac{2}{3} = 0.66666666...

\frac{1}{7} = 0.142857142

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It could be observed that Mario's claim is not a general principle which is applicable to all fractions with a prime denominator. Thus, I do not agree with his claim.

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Mashutka [201]

Answer:

(2x+1)(x+7)

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2x2+15x+7

For a polynomial of the form ax2+bx+c

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2x2+x+14x+7

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2 years ago
Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
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Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

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The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

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s = 6

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B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

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V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

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Answer:

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3 0
3 years ago
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