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Fittoniya [83]
3 years ago
14

Calculate the average of the following numbers 6g, 8g, 10g and 4g

Physics
1 answer:
kupik [55]3 years ago
3 0

Answer:

7g

Explanation:

To find the average, add all numbers, the divide by the amount of numbers there are. So

6 + 8+ 10 + 4 = 28

28 divided by 4 = 7

And just add g at the end... so 7g is your answer

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A graph shows how the temperature of a substance changes as energy is added steadily over time.
OlgaM077 [116]

Answer:

A flat, horizontal line  

Explanation:

A flat, horizontal line indicates a phase change.

The temperature does not increase because the added heat goes into converting one phase into another.

A is wrong. A downward-sloping line indicates that the temperature is decreasing with time.

C is wrong. An upward-sloping line indicates that the temperature is increasing with time.

8 0
3 years ago
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Help please <br><br><br> What is elastic potential energy
spin [16.1K]

Awnser:

Elastic Potential Energy. Elastic potential energy is Potential energy stored as a result of deformation of an elastic object,

Explanation:

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3 years ago
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The force of gravity produces acceleration in all C. freely falling objects and this is known as acceleration due to gravity

Explanation:

A body is said to be in free fall when there is only one force acting on the body: the force of gravity.

Gravity is a force that acts downward, i.e. towards the Earth's centre.

If we are near the Earth's surface, the magnitude of the force of gravity on a body is given by

F=mg

where:

m is the mass of the body

g is known as the acceleration of gravity , whose value near the Earth's surface is 9.8 m/s^2).

We can apply Newton's second law on an object in free-fall, to find its acceleration. In fact, we have:

F=ma

where F is the force acting on the body and a is its acceleration.

Solving for the acceleration,

a=\frac{F}{m}

And substituting F,

a=\frac{mg}{m}=g=9.8 m/s^2

Therefore, every object in free-fall accelerates at 9.8 m/s^2 towards the ground.

Learn more about free fall here:

brainly.com/question/1748290

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8 0
3 years ago
A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package hits the ground, how high
Lelu [443]

Answer:

The package was released at a height of 1015.296 meters.

Explanation:

The package is dropped at an initial velocity different of zero, decelerated and later accelerated by gravity. Let assume that final height is equal to zero, the final height is given by the following equation of motion:

y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2}

Where:

v_{o} - Initial velocity, measured in meters per second.

y - Final height, measured in meters.

y_{o} - Initial height, measured in meters.

t - Time, measured in seconds.

g - Gravitational constant, measured in meters per square second.

(Positive sign - Package is moving upward, Negative sign - Package is moving downward)

The initial height is now cleared:

y_{o} = y - v_{o}\cdot t - \frac{1}{2}\cdot g \cdot t^{2}

Given that y = 0\,m, v_{o} = 15\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}} and t = 16\,s, the final height of the package is:

y_{o} = 0\,m - \left(15\,\frac{m}{s} \right)\cdot (16\,s) - \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (16\,s)^{2}

y_{o} = 1015.296\,m

The package was released at a height of 1015.296 meters.

7 0
3 years ago
The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2 gas. Which co
ASHA 777 [7]

D. 2 in front of water and 1 in front of oxygen


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