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Helen [10]
3 years ago
7

An aluminum rod 17.400 cm long at 20°C is heated to 100°C. What is its new length? Aluminum has a linear expansion coefficient o

f 25 × 10-6 C-1.

Physics
1 answer:
NISA [10]3 years ago
3 0

Answer:

the new length is 17.435cm

Explanation:

the new length is 17.435cm

pls give brainliest

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The force produced by gravity on a mass is called
Yakvenalex [24]

Answer:

gravitational force

weight

Explanation:

5 0
3 years ago
What is a force field
amid [387]
Chiefly in science fiction) an invisible barrier of exerted strength or impetus.
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3 years ago
Consider a situation where a constant force of 25 N acts on an object having a mass of 2 kg for 3 seconds. What is the work done
blagie [28]

Answer:

Work done W =1406.25 J

Explanation:

Work done on a body can be calculated using newton's 2nd laws:

F=ma

\Rightarrow a=\frac{F}{m}

Hence acceleration of the block is given by:

\Rightarrow a=\frac{25}{2}=12.5m/s^2

Displacement of the object is given by:

\Rightarrow S=ut+\frac{1}{2}at^2

Substitute the values

\Rightarrow S=0*3+\frac{1}{2}(12.5)3^2

\Rightarrow S=56.25 m

Now work done is given by:

 W=F.S

W = 25×56.25

W =1406.25 J

3 0
3 years ago
Mark creates a graphic organizer to review his notes about electrical force. Which labels belong in the regions marked X and Y?
sveta [45]

Answer:

The correct answer is A

Explanation:

The question requires as well the attached image, so please see that below.

Coulomb's Law.

The electrical force can be understood by remembering Coulomb's Law, that  describes the electrostatic force between two charged particles. If the particles have charges q_1 and q_2, are separated by a distance r and are at rest relative to each other, then its electrostatic force magnitude on particle 1 due particle 2 is given by:

|F|=k \cfrac{q_1 q_2}{r^2}

Thus if we decrease the distance by half we have

r_1 =\cfrac r2

So we get

|F|=k \cfrac{q_1 q_2}{r_1^2}

Replacing we get

|F|=k \cfrac{q_1 q_2}{(r/2)^2}\\|F|=k \cfrac{q_1 q_2}{r^2/4}

We can then multiply both numerator and denominator by 4 to get

|F|=k \cfrac{4q_1 q_2}{r^2}

So we have

|F|=4 \left(k \cfrac{q_1 q_2}{r^2}\right)

Thus if we decrease the distance by half we get four times the force.

Then we can replace the second condition

q_{2new} =2q_2

So we get

|F|=k \cfrac{q_1 q_{2new}}{r_1^2}

which give us

|F|=k \cfrac{q_1 2q_2}{r_1^2}\\|F|=2\left(k \cfrac{q_1 q_2}{r_1^2}\right)

Thus doubling one of the charges doubles the force.

So the answer is A.

8 0
3 years ago
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Ninas measurements shown in the table here BEST represent a wave with
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They best represent a wave with zero energy and zero amplitude.

There are no measurements shown in a table that accompanies
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