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Helen [10]
3 years ago
7

An aluminum rod 17.400 cm long at 20°C is heated to 100°C. What is its new length? Aluminum has a linear expansion coefficient o

f 25 × 10-6 C-1.

Physics
1 answer:
NISA [10]3 years ago
3 0

Answer:

the new length is 17.435cm

Explanation:

the new length is 17.435cm

pls give brainliest

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Calculate the average speed of an airplane that traveled 1,100 miles in 3.5 hours
Ivan

Answer:

314.29 m/hrs

Explanation:

v = d / t

v = 1100 m / 3.5 hrs

v = 314.29 m/hrs

Note that I around the answer to the nearest hundredth. Hope this helps, thank you :) !!

3 0
3 years ago
Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object,which is at 500 K
Damm [24]

Explanation:

The given data is as follows.

       T_{1} = 400 K,     T_{2} = 500 K,  

\Delta Q = 25 kJ = 25000 J   (as 1 kJ = 1000 J)

Now, we will calculate the change in entropy as follows.

            \Delta S = \frac{\Delta Q}{\Delta T}

Putting the given values into the above formula as follows.

           \Delta S = \frac{\Delta Q}{\Delta T}

                      = \frac{25000 J}{(500 K - 400 K)}      

                      = 250 J/K

Hence, we can conclude that change in entropy is 250 J/K.

4 0
3 years ago
First, you will investigate purely vertical motion. The kinematics equation for vertical motion (ignoring air resistance) is giv
AlladinOne [14]

Answer: It takes 2.85 seconds.

Explanation: according to the question, the kinematics equation for vertical motion is

y(t) = y_{0} + v_{0} .t - \frac{1}{2} .gt^{2}

y₀ is the initial postion and equals 0 because it is fired at ground level;

v₀ is the initial speed and eqauls 14m/s;

g is gravity and it is 9.8m/s²;

y(t) is the final position and equals 0 because it is when the pumpkin hits the ground;

Rewriting the equation, we have:

0 + 14t - \frac{1}{2}.9.8.t^{2} = 0

14t - 4.9t² = 0

t(14 - 4.9t) = 0

For this equation to be zero,

t = 0 or

14 - 4.9t = 0

- 4.9t = - 14

t = \frac{14}{4.9}

t = 2.86

It takes 2.86 seconds for the pumpkin to hit the ground.

6 0
3 years ago
Currents during lightning strikes can be up to 50000 A (or more!). We can model such a strike as a 49500 A vertical current perp
Tema [17]

Answer:

59.4 N

Explanation:

The force exerted on a current-carrying wire due to a magnetic field perpendicular to the wire is given by

F=ILB

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

Here in this problem, we model the strike as a current-carrying wire, so we have:

I = 49,500 A is the current

L = 1 m is the length (we want to find the force per each meter of length)

B=12 G = 12\cdot 10^{-4} T is the strength of the magnetic field

Therefore, the force on each meter of the current due to the magnetic field is:

F=(49,500)(1)(12\cdot 10^{-4})=59.4 N

3 0
3 years ago
When you kick a soccer ball across a field it will eventually come to a stop. Does this prove or disapprove newton's first law o
jek_recluse [69]
I think its D. I am pretty sure 
6 0
3 years ago
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