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n200080 [17]
3 years ago
10

When the heart beats faster, blood vessels need to _____ more. open close move

Physics
2 answers:
Yuki888 [10]3 years ago
6 0
I'm pretty sure it is open more
snow_tiger [21]3 years ago
4 0

vessels need to open more.

You might be interested in
If a box is pushed 5.0 m across a floor using a force of 35 N, how much work was done?
aniked [119]

Answer:

175J

Explanation:

Work done is given by the product of the force applied and the distance travelled as a result of that force.

Or in formula , W=F×d

Thus,

W= 35 × 5.0=175 J or 1.8 e2 J

3 0
3 years ago
A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab
Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

       Fₓ-Fₓ = 0

       Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis  

        F_{y} + F_{y} - W =0

        2F_{y} = W

let's use trigonometry to find the angles

        tan θ = y / x

        θ = tan⁻¹ (0.30 / 0.50 L)

        θ = tan⁻¹ (0.30 / 0.50 15)

        θ = 2.29º

the components of stress are

         F_{y} = T sin θ

we substitute

       2 T sin θ = W

       T = W / 2sin θ

        T = \frac{ 800}{ 2sin 2.29}

        T = 10010 N

4 0
3 years ago
“DNA...”
GaryK [48]

Answer:

3. is made of nucleotides

7 0
2 years ago
Can you help me with this?
Natasha2012 [34]

Answer:

no

Explanation:

so basically I am domb so I can not help you

4 0
2 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim
never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

\text{Distance}=20\times 0.5=10\ m

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

\text{Distance}=u\times 0.5=0.5u\ m

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0

u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s

Maximum speed of the car by which it will not hit the deer is 25.1 m/s

5 0
2 years ago
Read 2 more answers
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