The total revenue for the event would the total amount earned from the tickets sold. So if x people attended the event, then there would be $(161x). We must keep in mind though the the maximum seating is 76 876. That means that the maximum revenue that can be earned must not exceed $(161)(76 867) = .
Hence we have f(x) = 161x where 0 ≤ x ≤ 76867.
From this, we can see that the domain is [0, 76867] while range is [0, 12375587]<span>.</span>
Half of 110 is 55 so the answer is 55
Answer:
33%
Step-by-step explanation:
h steps:
Step 1: We make the assumption that 51 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$.
Step 3: From step 1, it follows that $100\%=51$.
Step 4: In the same vein, $x\%=17$.
Step 5: This gives us a pair of simple equations:
$100\%=51(1)$.
$x\%=17(2)$.
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{51}{17}$
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{17}{51}$
$\Rightarrow x=33.33\%$
Therefore, $17$ is $33.33\%$ of $51$.
There’s nothing so let’s just go with C
