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Sphinxa [80]
2 years ago
15

Please can you help me with this because I had to post twice

Mathematics
1 answer:
steposvetlana [31]2 years ago
4 0

Answer:

y=11

Step-by-step explanation:

3y=y+22

3y-y=y-y+22

2y=22

y=11

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Suppose that $1,000 is deposited into an account that yields 0.85% interest, compounded annually.
andrey2020 [161]
<h3>Answer:  1034.44 dollars</h3>

=====================================

Work Shown:

A = P*(1+r/n)^(n*t)

A = 1000*(1+0.0085/1)^(1*4)

A = 1034.43596172007

A = 1034.44

---------------------

Notes:

  • P = 1000 is the deposit or principal
  • r = 0.0085 is the decimal form of the annual interest rate of 0.85%; we can say 0.85% = 0.85/100 = 0.0085
  • n = 1 represents how many times per year we're compounding the money (ie annually)
  • t = 4 = number of years
  • The result of 1034.44 dollars is only possible if you do not withdraw any of the money in the four year time period.
4 0
3 years ago
Find the area of the shaded region. Round the the nearest tenth.
Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = \frac{\theta}{360^{\circ} }\pi r^2

Area of sector = \frac{123}{360} \times 3.14 \times (18.6)^2

Area of sector = 371.157 m^2

Area of triangle = \frac{1}{2} \times a \times b \times Sin x

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = \frac{1}{2} \times 18.6 \times 18.6 \times Sin 123

Area of triangle = 145.073 m^2

So, Area of shaded region = Area of sector - Area of triangle

                                            =371.157 m^2-145.073 m^2

                                            =226.084 m^2

Hence the area of the shaded region is 226.084 sq.m.

5 0
3 years ago
PLEASE HELP WITH THIS QUESTION​
Radda [10]

Answer:

The correct answer is Redbirds

P = 4/5 = 0.8

4 0
2 years ago
Helppp plzzzzz mathhh
spayn [35]

Answer:

A) f^-1(x)=(x-8)^3+2

Step-by-step explanation:

To find the function inverse, switch the x with y and solve for y.

y=\sqrt[3]{x-2}+8 \\\\x=\sqrt[3]{y-2}+8\\\\(x-8)^3 = y-2\\\\ (x-8)^3 + 2 = y

5 0
3 years ago
I need help please, i dont understand
jenyasd209 [6]

9514 1404 393

Answer:

  (a)  none of the above

Step-by-step explanation:

The largest exponent in the function shown is 2. That makes it a 2nd-degree function, also called a quadratic function. The graph of such a function is a parabola -- a U-shaped curve.

The coefficient of the highest-degree term is the "leading coefficient." In this case, that is the coefficient of the x² term, which is 1. When the leading coefficient of an even-degree function is positive, the U curve has its open end at the top of the graph. We say it "opens upward." (When the leading coefficient is negative, the curve opens downward.)

This means the bottom of the U is the minimum value the function has. For a quadratic in the form ax²+bx+c, the horizontal location of the minimum on the graph is at x=-b/(2a). This extreme point on the curve is called the "vertex."

This function has a=1, b=1, and c=3. The minimum of the function is where ...

  x = -b/(2·a) = -1/(2·1) = -1/2

This value is not listed among the answer choices, so the correct choice for this function is ...

  none of the above

__

The attached graph of the function confirms that the minimum is located at x=-1/2

_____

<em>Additional comment</em>

When you're studying quadratic functions, there are few formulas that you might want to keep handy. The formula for the location of the vertex is one of them.

8 0
2 years ago
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