Express as a difference.

Riya is applying mulch to her garden. she applies it at a rate of 250 , 000 cm 3 250,000 cm 3 250, comma, 000, start text, space

Tatiana [17]

The rate in

$\frac{ {m}^{3} }{ {m}^{2} } \: is \:0.25\frac{ {m}^{3} }{ {m}^{2} }$

<h3>How to find rate is riya applying mulch in m^3/m^2 ?</h3>

given that riya applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space.

we already know that 1m = 100cm.

so, each side of this cube is 100cm in length.

so, $100 \times 100 \times 100 \: {cm}^{3} \: in \: {m}^{3}$

To find what is the volume in cubic metres.

$\frac{250000}{10000000} = \frac{1}{4} = 0.25 \frac{ {m}^{3} }{ { m}^{2} }$

so, the rate is $0.25 \frac{ {m}^{3} }{ {m}^{2} }$

Learn more about problems on garden, refer :

https://brainly.in/question/50618467

#SPJ4

Disclaimer : This question was given incomplete on portal.Here is complete question.

Question : Riya is applying mulch to her garden.She applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space. At what rate is riya applying mulch in m^3/m^2

8 0

2 years ago

Solve the following equations | 3x + 3/7 | = 2 1/3

jasenka [17]

Answer:

X∈ $\frac{5}{63}, -\frac{23}{63}$

Step-by-step explanation:

7 0

3 years ago

A survey is taken among customers of a fast-food restaurant to determine preference for hamburger or chicken. Of 200 respondents

kicyunya [14]

Answer:

Hamburger Chicken

Adults 65 60 125

children 55 20 75

120 80 200

a)What is the probability that a randomly selected individual is an adult?

Total no. of adults = 125

Total no. of people 200

The probability that a randomly selected individual is an adult = $\frac{125}{200}=0.625$

b) What is the probability that a randomly selected individual is a child and prefers chicken?

No. of child prefers chicken = 20

The probability that a randomly selected individual is a child and prefers chicken= $\frac{20}{200}=0.1$

c)Given the person is a child, what is the probability that this child prefers a hamburger?

No. of children prefer hamburger = 55

No. of child = 75

The probability that this child prefers a hamburger= $\frac{35}{75}=0.46$

d) Assume we know that a person has ordered chicken, what is the probability that this individual is an adult?

No. of adults prefer chicken = 60

No. of total people like chicken = 80

A person has ordered chicken, the probability that this individual is an adult= $\frac{60}{80}=0.75$

3 0

3 years ago

Calc 3 iiiiiiiiiiiiiiiiiiiiiiiiiiii

Lilit [14]

Take the Laplace transform of both sides:

L[y'' - 4y' + 8y] = L[δ(t - 1)]

I'll denote the Laplace transform of y = y(t) by Y = Y(s). Solve for Y :

(s²Y - s y(0) - y'(0)) - 4 (sY - y(0)) + 8Y = exp(-s) L[δ(t)]

s²Y - 4sY + 8Y = exp(-s)

(s² - 4s + 8) Y = exp(-s)

Y = exp(-s) / (s² - 4s + 8)

and complete the square in the denominator,

Y = exp(-s) / ((s - 2)^2 + 4)

Recall that

L⁻¹[F(s - c)] = exp(ct) f(t)

In order to apply this property, we multiply Y by exp(2)/exp(2), so that

Y = exp(-2) • exp(-s) exp(2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-s + 2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-(s - 2)) / ((s - 2)² + 4)

Then taking the inverse transform, we have

L⁻¹[Y] = exp(-2) L⁻¹[exp(-(s - 2)) / ((s - 2)² + 4)]

L⁻¹[Y] = exp(-2) exp(2t) L⁻¹[exp(-s) / (s² + 4)]

L⁻¹[Y] = exp(2t - 2) L⁻¹[exp(-s) / (s² + 4)]

Next, we recall another property,

L⁻¹[exp(-cs) F(s)] = u(t - c) f(t - c)

where F is the Laplace transform of f, and u(t) is the unit step function

$u(t) = \begin{cases}1 & \text{if }t \ge 0 \\ 0 & \text{if }t < 0\end{cases}$

To apply this property, we first identify c = 1 and F(s) = 1/(s² + 4), whose inverse transform is

L⁻¹[F(s)] = 1/2 L⁻¹[2/(s² + 2²)] = 1/2 sin(2t)

Then we find

L⁻¹[Y] = exp(2t - 2) u(t - 1) • 1/2 sin(2 (t - 1))

and so we end up with

y = 1/2 exp(2t - 2) u(t - 1) sin(2t - 2)

7 0

3 years ago

Which equation represents a parabola that opens upward has a minimum at x=3 and has a line of symmetry at x=3

umka2103 [35]

Answer:

$y=x^2-6x+5$

Step-by-step explanation:

Let us consider the equation $y=x^2-6x+5$

For a quadratic equation in a standard form, $y=ax^2+bx+c$ , the axis of symmetry is the vertical line $x = \frac{-b}{2a}$ .

Here in this case we have, $a=1, b=-6 , c =5$

Putting the values we get,

$x = \frac{-(-6)}{2\times 1} = \frac{6}{2} =3$

We can see that the axis of symmetry is x=3 and the graph is giving minimum at x=3.

Therefore, the required equation is $y=x^2-6x+5$ . Refer the image attached.

4 0

3 years ago

Read 2 more answers