Respuesta:
2400 mL
Explicación:
Paso 1: Información dada
- Volumen de solución: 3 L (3000 mL)
- Concentración de naranja: 20 % v/v
Paso 2: Calcular el volumen de naranja
La concentración de naranja es de 20 % v/v, es decir, cada 100 mL de solución hay 20 mL de naranja.
3000 mL Sol × 20 mL Naranja/100 mL Solución = 600 mL Naranja
Paso 3: Calcular el volumn de agua
El volumen de soluciónes igual a la suma de los volúmenes de naranja y agua.
VSolución = VNaranja + VAgua
VAgua = VSolución - VNaranja
VAgua = 3000 mL - 600 mL = 2400 mL
Answer:
here it is
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Answer:
Electrical Energy
Explanation:
Batteries store chemical energy and change it to electrical energy.
Enzymes are biological molecules (typically proteins) that significantly speed up the rate of virtually all of the chemical reactions that take place within cells. They are vital for life and serve a wide range of important functions in the body, such as aiding in digestion and metabolism.
Answer : The number of moles of ethane required will be 0.166 mole.
Explanation :
First we have to calculate the heat absorbed by water.

where,
q = heat absorbed = ?
m = mass of water = 851 g
c = specific heat of water = 
= final temperature = 
= initial temperature = 
Now put all the given values in the above formula, we get:

(1 kJ = 1000 J)
Now we have to calculate the moles of ethane required.

where,
= enthalpy of combustion of ethane = 1560.7 kJ/mol (standard value)
q = heat absorbed = 259.67 kJ
n = number of moles of ethane = ?



Therefore, the number of moles of ethane required will be 0.166 mole.