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Anestetic [448]
3 years ago
13

Waves are caused by blank and tides are caused by blank

Chemistry
1 answer:
Sergio [31]3 years ago
7 0

Answer:

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest. ... The gravitational pull of the sun and moon on the earth also causes waves.

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996). ... Tidal forces are based on the gravitational attractive force.

If the Tides is working then out “ High and low tides are caused by the Moon. The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. These bulges of water are high tides“.

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In a certain crystalline material the vacancy concentration at 25 c is one-fourth that at 80
Luba_88 [7]

At 93 °C, the vacancy concentration will be three times that at 80°C.

The formula for the vacancy concentration in a crystal is a form of the <em>Arrhenius equation</em>.

In logarithmic form, the equation is

ln(<em>N</em>_2/<em>N</em>_1) = (-<em>Q</em>/<em>R</em>)(1/<em>T</em>_2-1/<em>T_</em>1)

where

• Q = the energy required for vacancy formation

• <em>N</em>_2 = the vacancy concentration at <em>T</em>_2

• <em>N</em>_1 = the vacancy concentration at <em>T</em>_1

• <em>R</em> = the gas constant [8.314 J·K^(-1)mol^(-1)]

Let <em>N</em>_80 represent the vacancy concentration at 80 °C.

At 25 °C, ln(<em>N</em>_25/<em>N</em>_80) = ln(0.25<em>N</em>_80/<em>N</em>_80) = ln0.25 = -1.386

∴ -1.386 =(-<em>Q</em>/<em>R</em>)(1/298.15 – 1/353.15) = -1.306 × 10^(-4) × (<em>Q</em>/<em>R</em>)

<em>Q</em>/<em>R</em> = (-1.386)/[-1.306 × 10^(-4)] = 10 620

At <em>T</em>_2, ln(<em>N</em>_<em>T</em>2/<em>N</em>_80) = ln[(3<em>N</em>_80)/<em>N</em>_80] = ln3 = 1.099

∴ 1.099 = -10 620(1/<em>T</em>_2 – 1/353.15) = -10 620/<em>T</em>_2 + 10 620/353.15

= -10 620/<em>T</em>_2  + 30.072

10 620/<em>T</em>_2 = 30.072 – 1.099 = 28.97

<em>T</em>_2 = 10 620/28.97 = 366.4 K = 93 °C

3 0
3 years ago
147 J is what kind of quantity
ioda

Answer:

quantitative data

Explanation:

hope this helped

3 0
4 years ago
What can help engineers develop ways to prevent rusting?
muminat

Answer: Understanding oxidation-reduction reactions

Explanation:

Rusting occurs when electrons are exchanged between iron and oxygen.

7 0
2 years ago
Scientists dye cells using fluorescent molecules that bind to the cell membrane so that the cells can be seen under a microscope
xenn [34]
B is correct. cause with microscope you look at the surface
7 0
3 years ago
Read 2 more answers
given a k value of 0.43 for the following aqueous equilibrium suppose sample z is placed into water such that its original conce
serious [3.7K]

Answer:

Less than 0.033 M:

[Z]_{eq}=2.4x10^{-3}M

Explanation:

Hello,

In this case, the described equilibrium is:

2A+B\rightarrow 2Z

Thus, the law of mass action is:

K=\frac{[Z]^2}{[A]^2[B]}=0.43

Nevertheless, given the initial concentration of Z that is 0.033 M, we should invert the equilibrium since the reaction will move leftwards:

\frac{1}{K}=\frac{[A]^2[B]}{[Z]^2}=\frac{1}{0.43}=2.33

Know, by introducing the change x due to the reaction extent, we can write:

2.33=\frac{(2x)^2*x}{(0.033-2x)^2}

Which has the following solution:

x_1=2.29M\\x_2=0.0181M\\x_3=0.0153M

But the correct solution is x_3=0.0152M since the other solutions make the equilibrium concentration of Z negative which is not possible. In such a way, its concentration at equilibrium is:

[Z]_{eq}=0.033M-2(0.0153M)

[Z]_{eq}=2.4x10^{-3}M

Which is clearly less than 0.033 M since the addition of a product shift the reaction leftwards in order to reestablish equilibrium (Le Chatelier's principle).

Regards.

6 0
3 years ago
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