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Alekssandra [29.7K]
3 years ago
6

PLZ HELP ASAP!!!! I WILL GIVE BRAINLIEST!!!!!!!!!!

Chemistry
2 answers:
guajiro [1.7K]3 years ago
7 0

Answer:

Explanation:

D. Parasitism

The mosquito is taking blood from the human, and injecting malaria and other irritations  

Andrej [43]3 years ago
5 0
The relationship of parasitism is shown in the image above; the mosquito carries the protozoan organism (plasmodium), uses the host as a habitat and infects humans. Hope this helps ;)
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What would mix the best with water?
yanalaym [24]

Answer:

A)nonpolar molecule

Explanation:

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4 years ago
On a mission to a newly discovered planet, an astronaut finds copper abundances of 69.15 % for 63cu and 30.85 % for 65cu. what i
ioda
The relative atomic mass is the weighted average mass of elements relative to 1/12th the mass of a 12-C atom.
Isotopes are atoms of the same element with different masses , in other words different numbers of neutrons.
Relative atomic mass =sum of (mass x percentage )
R.a.m = 62.9300 x 69.15% + 64.9200 x 30.85%
= 43.52 + 20.03
= 63.55 amu
8 0
3 years ago
Read 2 more answers
What are the half-reactions for a galvanic cell with aluminum and gold electrodes?
s344n2d4d5 [400]

Answer: B

Explanation:

4 0
2 years ago
Please help<br><br> SOS<br><br> and explain please if you know how
vfiekz [6]

Answer:

<h2>1 N2+ 1 O2 are two N atoms and two O atoms.</h2>

<h3>In NO, there is one N and one O atom.</h3>

For both sides to be the same, there have to be 2 NO molecules, as 2 NO molecules contain 2 N atoms and 2 O atoms, just like starting products of the reaction.

8 0
3 years ago
The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine
Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

  • Specific heat of liquid bromine (c): 0.226 J/g.K
  • Volume of bromine (V): 10.0 mL
  • Initial temperature: 25.00 °C
  • Final temperature: 27.30 °C
  • Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0
3 years ago
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