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ratelena [41]
3 years ago
6

Which statement about stage 3 NREM is accurate?

Physics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

hope

that helps

Explanation:

D. The sleeper's heart rate, blood pressure, and breathing rate drop to their lowest levels.

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A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
Elenna [48]

The tension in the cable is 23.2 N

<h3>What is the tension in the string?</h3>

The tension in the cable can be resolved into horizontal and vertical forces Tcosθ and Tsinθ respectively.

Tcosθ, is acting perpendicularly, Tcosθ = 0

Taking moments about the pivot:

Tsinθ * 2.2 = 4 * 9.8 * 0.7

Solving for θ;

θ = tan⁻¹(1.4/2.2) = 32.5°

T = 27.44/(sin 32.5 * 2.2)

T = 23.2 N

In conclusion, the tension in the cable is determined by taking moments about the pivot.

Learn more about moments of forces at: brainly.com/question/23826701

#SPJ1

3 0
2 years ago
How much work will it take to lift a 2-kg pair of hiking boots 2 meters off the
AnnyKZ [126]

Answer:

Option C - 39.2 J

Explanation:

We are given that;

Mass; m = 2 kg.

Distance moved off the floor;d = 10 m.

Acceleration due to gravity;g = 9.8 m/s².

We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

Formula for this force is;

Force = mass x acceleration due to gravity

Force = 2 × 9.8 = 19.2 N

∴ Work done = 19.6 × 2

Work done = 39.2 J.

Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.

7 0
3 years ago
Read 2 more answers
A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2m/s to 4 m/s?
Vitek1552 [10]
Here, Initial momentum = mu = 6*2 = 12 Kg m/s
Final momentum = mv = 6*4 = 24 Kg m/s

In short, Your Answer would be Option C

Hope this helps!
6 0
3 years ago
Read 2 more answers
List the three types of symbiotic relationships. For each type of symbiotic relationship, explain how the two organisms are affe
Virty [35]
<span>The three major types of symbiosis are mutualism, where both species benefit, commensalism, where one species benefits and the other is unaffected, and parasitism, where one species benefits and the other is harmed. Symbiotic relationships can occur within an organism's body or outside of it.                                                                                                                                                                              </span><span>Examples of mutualism include the relationship between single-celled organisms or animals that incorporate algae into their bodies. They give the algae necessary nutrients, and in return receive chemical energy from the photosynthetic algae. Animals that have this sort of relationship include some sponges, sea anemones and clams. Examples of commensalism include remora fish attaching to the bodies of sharks and eating scraps of food that escape their jaws, and barnacles living on the jaws of whales with a similar feeding strategy. Plants have commensal relationships as well, such as many orchids that grow on taller plants and benefit from the additional sunlight they obtain, without actually stealing nutrients from the host plant. Parasitic relationships are many, and parasites include all disease-causing organisms. This category also includes insects such as fleas that suck the blood of hosts externally. Parasitism is a very efficient strategy for organisms, and parasites often lose many of the features of non-parasitic life forms, instead relying on their hosts for many of the functions of life.</span>
5 0
3 years ago
The velocity of the transverse waves produced by an earthquake is 8.9 km/s, and that of the longitudinal waves is 5.1 km/s. A se
Brrunno [24]

Answer: The distance is 723.4km

Explanation:

The velocity of the transverse waves is 8.9km/s

The velocity of the longitudinal wave is 5.1 km/s

The transverse one reaches 68 seconds before the longitudinal.

if the distance is X, we know that:

X/(9.8km/s) = T1

X/(5.1km/s) = T2

T2 = T1 + 68s

Where T1 and T2 are the time that each wave needs to reach the sesmograph.

We replace the third equation into the second and get:

X/(9.8km/s) = T1

X/(5.1km/s) = T1 + 68s

Now, we can replace T1 from the first equation into the second one:

X/(5.1km/s) = X/(9.8km/s) + 68s

Now we can solve it for X and find the distance.

X/(5.1km/s) - X/(9.8km/s) = 68s

X(1/(5.1km/s) - 1/(9.8km/s)) = X*0.094s/km= 68s

X = 68s/0.094s/km = 723.4 km

6 0
4 years ago
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