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mario62 [17]
3 years ago
13

Refer to the following balanced equation in which ammonia reacts with nitrogen monoxide to produce nitrogen and water. 4NH3(g) +

6NO(g) → 5N2(g) + 6H2O(1) How many moles of NH3 are necessary to produce 0.824 mol N2 ?
___ mol NH3 ​
Chemistry
1 answer:
grigory [225]3 years ago
5 0

Answer:

0.659 mol

Explanation:

n(NH3)/n(N2) = 4/5

n(NH3) = 4/5×0.824

= 0.659 mol

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Nitrogen gas reacts with hydrogen gas to produce ammonia. How many liters of hydrogen gas at 95kPa and 15∘C are required to prod
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Answer:

222.30 L

Explanation:

We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:

Mass of NH₃ = 100 g

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= 14 + 3

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Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

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Pressure (P) = 95 KPa

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Gas constant (R) = 8.314 KPa.L/Kmol

Volume (V) =?

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95 × V = 8.82 × 8.314 × 288

95 × V = 21118.89024

Divide both side by 95

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V = 222.30 L

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Answer:

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When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum

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