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KonstantinChe [14]
3 years ago
15

How is rubidium used

Chemistry
1 answer:
Virty [35]3 years ago
6 0

Answer:

Rubidium is used in vacuum tubes as a getter, a material that combines with and removes trace gases from vacuum tubes. It is also used in the manufacture of photocells and in special glasses. Since it is easily ionized, it might be used as a propellant in ion engines on spacecraft.

Symbol: Rb (37)

Atomic Weight: 85.4678

Atomic Number: 37

Number of Stable Isotopes: 1 (View all isotope .

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How much heat will be transferred when 0.54g of sulfur reacts with 0.54g of oxygen to produce sulfur trioxide according to the f
Alik [6]

Answer:

-4.4 kJ

Explanation:

5 0
3 years ago
If a substance has a high hydronium concentration, the substance has a ____ pH.
aalyn [17]

Answer: low pH

Hydronium is H^+ and acids give hydronium ions to water solution.

PH = -log H^+ concentration. The higher the concentration, the lower pH value

4 0
3 years ago
Which of the following is true about extinction? A. Only one extinction has occurred during the Earth's history. B. Plant specie
ycow [4]

Answer:

C. Extinctions have occurred many times throughout the Earth's history.

Explanation:

8 0
3 years ago
Read 2 more answers
Hi, Can someone help me with this question, please! It's due tonight!
-BARSIC- [3]

Answer:

24.0 g C₃H₈

Explanation:

To find the mass of C₃H₈, you need to (1) convert grams CO/H₂ to moles CO/H₂ (via molar mass), then (2) convert moles CO/H₂ to moles C₃H₈ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles C₃H₈ to grams C₃H₈ (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs in the given values.

Molar Mass (CO): 12.011 g/mol + 15.998 g/mol

Molar Mass (CO): 28.009 g/mol

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

Molar Mass (C₃H₈): 3(12.011 g/mol) + 8(1.008 g/mol)

Molar Mass (C₃H₈): 44.097 g/mol

3 CO + 7 H₂ ----> 1 C₃H₈ + 3 H₂O
^           ^              ^

45.8 g CO           1 mole              1 mole C₃H₈          44.097 g
-----------------  x  ------------------  x  --------------------  x  ------------------  =
                           28.009 g           3 moles CO            1 mole

=  24.0 g C₃H₈

87.3 g H₂           1 mole           1 mole C₃H₈          44.097 g
----------------  x  ---------------  x  ---------------------  x  -----------------  =  
                          2.016 g           7 moles H₂             1 mole

=  273 g C₃H₈

It was necessary to find the mass of the products from both of the reactants because you did not know which one was the limiting reagent. The limiting reagent is the reactant which is completely used up first. Because CO produced the smaller amount of product, it must be the limiting reagent. Therefore, the actual amount of C₃H₈ produced is 24.0 grams.

4 0
2 years ago
Find the energy of a photon of light if the wavelength of the light wave is 6.88 x 10–7m
stepan [7]
Use the formula E=hv, h=plancks constant and v=frequency
use the formula c=v*lambda to find v
the answer will be 2.88*10^-23J

6 0
3 years ago
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