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3 years ago

Be good peeps The adult height of a male is about 1.19

Mathematics

1 answer:

kogti [31]3 years ago

4 0

Answer:

I think that the answer is 2.07

Step-by-step explanation:

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What is part a line has one endpoint and continues in one direction

LenaWriter [7]

Well the line is called a ray because because the left of the endpoint is a dot and it doesn't go anywhere. So your answer is a ray.

hope that helped

8 0

3 years ago

Read 2 more answers

A scarf is a triangle with two perpendicular sides that are the same length. Which two terms describe the triangular scarf? A. i

timurjin [86]

Answer:

A triangular scarf is an isosceles right triangle.

Step-by-step explanation:

Given: A scarf is a triangle with two perpendicular sides that are the same length.

We have to name which two terms describe a triangular scarf.

Isosceles triangle is a triangle with length of two of its sides equal.

Right angled triangle is a triangle in which one angle is a right angle.

Given :

The two sides of scarf are perpendicular to each other.

Thus, the angle formed between them is 90°. Hence, right angled triangle.

Also, length of two sides are same, Hence isosceles triangle.

Thus,a triangular scarf is an isosceles right triangle.

6 0

3 years ago

HELPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!

aliya0001 [1]

Answer:

use photo math ;) hope this helps

Step-by-step explanation:

it's very good

3 0

3 years ago

Read 2 more answers

Aubrey claims that if the dimensions of the parallelogram shown are doubled then the area of the larger parallelogram will be 4

djyliett [7]

Answer:

True

Step-by-step explanation:

Even though we cannot see the parallelogram, we can assume the dimensions of the original parallelogram is height= 3 and base= 6.

If we double the dimensions, we get:

height=6 band base=12.

The area of the original parallelogram is 18 square units.

The area of the enlarged parallelogram is 6×12= 72 square units.

Now,

$\frac{72}{18} = 4$

Hence, the area of the larger parallelogram is 4 times more than the original.

4 0

3 years ago

Read 2 more answers

Simplify each expression. Assume that all variables are positive.

kozerog [31]

Q1. The answer is $\frac{8x^{3}y^{6} }{27}$

$( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} } \\ \\ 
 \frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\ \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=$
$\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\ \\ 
 (x^{a} )^{b} = x^{a*b} \\ \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } = \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} =$
$= \frac{8x^{3}y^{6} }{27}$

Q2. The answer is 1/16

$(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ 
$
$\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}$

Q3. The answer is $a^{ \frac{7}{6} }$

$a^{ \frac{2}{3} } * a^{ \frac{1}{2} } \\ \\ 
 x^{a}* x^{b} =x^{a+b} \\ \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }$

7 0

3 years ago