Draw Graph for the derivation of three equations of Motion
1 answer:
Answer:
Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say
Explanation:
Derive v = u + at by Graphical Method. Consider the velocity – time graph of a body shown in the below Figure
Derive s = ut + (1/2) at2 by Graphical Method. Velocity so time graph to derive the equations of motion.
Derive v2 = u2 + 2as by Graphical Method. Velocity–Time graph to derive the equations of motion.
I hope you understand now
enjoy your day
#Captainpower :)❤❤
You might be interested in
To solve the exercise it is necessary to take into account the concepts of wavelength as a function of speed.
From the definition we know that the wavelength is described under the equation,
Where,
c = Speed of light (vacuum)
f = frequency
Our values are,
Replacing we have,
<em>Therefore the wavelength of this wave is </em>
Answer:
a= - 6.667 m/s²
Explanation:
Given that
The initial speed of the box ,u= 20 m/s
The final speed of the box ,v= 0 m/s
The distance cover by box ,s= 30 m
Lets take the acceleration of the box = a
We know that
v²= u ² + 2 a s
Now by putting the values in the above equation we get
0²=20² + 2 a x 30
a= - 6.667 m/s²
Negative sign indicates that velocity and acceleration are in opposite direction.
Therefore the acceleration of the box will be - 6.667 m/s² .