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lisov135 [29]
2 years ago
7

Draw Graph for the derivation of three equations of Motion​

Physics
1 answer:
Over [174]2 years ago
5 0

Answer:

Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say

Explanation:

Derive v = u + at by Graphical Method. Consider the velocity – time graph of a body shown in the below Figure

Derive s = ut + (1/2) at2 by Graphical Method. Velocity so time graph to derive the equations of motion.

Derive v2 = u2 + 2as by Graphical Method. Velocity–Time graph to derive the equations of motion.

I hope you understand now

enjoy your day

#Captainpower :)❤❤

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There's not enough information to find an answer.

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the glider gives up some gravitational potential energy, which
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good, but we can't calculate the difference in potential energy
without knowing the mass of the glider.

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3 years ago
Look at the equation shown below. What does the letter Q represent?
Westkost [7]

Answer:

Explanation:

I=CURRENT

Q=CHARGE

t=TIME

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What is the only thing that can change
krok68 [10]

Answer:

Since velocity is a speed and a direction, there are only two ways for you to accelerate

Explanation:

change your speed or change your direction—or change both.

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On the way home from school, Taylor's car runs out of gas. He has to walk 25m north and 10m west in order to reach the nearest g
spin [16.1K]

Answer:

<em>The distance is 35 m and the magnitude of the displacement is 26.93 m</em>

Explanation:

<u>Displacement  and Distance</u>

These are two related concepts. A moving object constantly travels for some distance at defined periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

This sum is calculated independently of the direction the object moves.

The displacement only takes into consideration the initial and final positions of the object. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.

Taylor walks 25 m north and 10 m west. The total distance is the sum of both numbers:

d = 25 m + 10 m = 35 m

To calculate the displacement, we need to know the final position with respect to the initial position. If we set the coordinates of Taylor's car as the origin (0,0), then his final position is (-10,25), assuming the west direction is negative and the north direction is positive.

The magnitude of the displacement is the distance from (0,0) to (-10,25):

D=\sqrt{(25-0)^2+(-10-0)^2}

D=\sqrt{625+100}=\sqrt{725}

D = 26.93 m

The distance is 35 m and the magnitude of the displacement is 26.93 m

8 0
3 years ago
Place the left charge at the 2 cm position and the right one at the 4 cm position. Vary the left and right charge to the values
Vlad1618 [11]

Answer:

Explanation:

Force between two charges can be expressed as follows

F = k q₁ q₂ / d²

q₁ and q₂ are two charges , d is distance between them , k is a constant whose value is 9 x 10⁹

distance between charges is fixed which is 4 -2 = 2 cm = 2 x 10⁻² m

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= 9 x 10⁹ x 1 x 4 x 10⁻¹² / ( 2 x 10⁻² )²

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= 9 x 10 = 90 N

force between 2μC and  2μC

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= 9 x 10 = 90 N

force between 1μC and  2μC

= 9 x 10⁹ x 1 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 4.5 x 10 = 45 N

force between 1μC and  8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 18 x 10 = 180 N

force between 2μC and  8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 36 x 10 = 360 N

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1μC                     4μC                  90 N

4μC                   1μC                    90 N

2μC                  2μC                    90 N

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1μC                  8μC                    180 N

2μC                  8μC                  360 N

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