Answer:
The velocity of the student has after throwing the book is 0.0345 m/s.
Explanation:
Given that,
Mass of book =1.25 kg
Combined mass = 112 kg
Velocity of book = 3.61 m/s
Angle = 31°
We need to calculate the magnitude of the velocity of the student has after throwing the book
Using conservation of momentum along horizontal direction
Put the value into the formula
Hence, The velocity of the student has after throwing the book is 0.0345 m/s.
Answer: I would say the object with the Lower velocity because Lighter with Higher velocity makes it heavy, velocity is how heavy something is so the lighter it is the less difficult it will be to catch.
Answer:
Explanation:
Givens
Vi = 10 m/s
Vf = 40 m/s
a = 3 m/s^2
Formula
a = (vf - vi) /t Substitute the givens into this formuls
Solution
3 = (40 - 10) / t Multiply both sides by t
3*t = t(40 - 10)/t Combine. Cancel t's on the right
3*t = 30 Divide by 3
3t/3 = 30 / 3
Answer: t = 10 seconds.
