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san4es73 [151]
3 years ago
12

Can someone help me due at 1:00 PM plus 100 points questions B,C,D

Physics
2 answers:
vagabundo [1.1K]3 years ago
6 0
<h3>b. ML </h3><h3>c. M</h3><h3>d. Kg</h3>

<h3>Hope it helps...</h3>
Alenkasestr [34]3 years ago
5 0

Answer:

B is 1

C is 2 I believe

D I'm pretty sure is 3

Explanation:

you can look the answers up :D!

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Cutting down trees can decrease the amount of water vapor entering the air through the processes of ____?
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✿  Transpiration is the process by which water is carried through plants from roots and release water vapor through their leaves.

✿  Cutting down trees can decrease the amount of water vapor entering the air through the processes of <u>Transpiration</u>

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2 years ago
an object is moving east with a constant speed of 20m/s for 4 seconds.What is the object's acceleration
Tamiku [17]

The objects acceleration is 6m/s.

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2 years ago
How much energy is required to move 2 electrons through a potential difference of 1.0 x 10^ 2 volts?
Ksenya-84 [330]
Charge of electron = 1.6×10−¹⁹

(1.6×10−¹⁹)(1×10²) (2e)

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3 0
2 years ago
A grain silo is shown below:grain silo formed by cylinder with radius 5 feet and height 175 feet and a half sphere on the topwha
nekit [7.7K]
Find the volume of the bottom and top separately and then add them.
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(22/7)(5^2)•175=13750 ft^3

The volume of a sphere is
V=(4/3)(22/7)r^3
where r is the radius. Here that's also 5 since it fits on the cylinder.
Also we only want half the sphere so use
V=(2/3)(22/7)•5^3=261.9 ft^3
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6 0
3 years ago
The International Space Station has a mass of 1.8 × 105 kg. A 70.0-kg astronaut inside the station pushes off one wall of the st
Aleonysh [2.5K]

Answer:

a = 5.83 \times 10^{-4} m/s^2

Explanation:

Since the system is in international space station

so here we can say that net force on the system is zero here

so Force by the astronaut on the space station = Force due to space station on boy

so here we know that

mass of boy = 70 kg

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now we know that

F = ma

F = 70(1.50) = 105 N

now for the space station will be same as above force

F = ma

105 = 1.8 \times 10^5 (a)

a = \frac{105}{1.8 \times 10^5}

a = 5.83 \times 10^{-4} m/s^2

3 0
3 years ago
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