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kondor19780726 [428]

3 years ago

6

90Th234 What element atom is formed when the thorium nucleus is оруулах-decomposed?

1 answer:

Archy [21]3 years ago

8 0

This question is from course hero.

So better check this question!

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a business that sells products to teens would most likely create a website with a title ending in what suffix?

Nataliya [291]

I think you forgot to give the options along with your question. I am answering the question based on my knowledge and research. <span>A business that sells products to teens would most likely create a website with a title ending in .com. I hope that this is the answer that has actually come to your great help.</span>

3 0

3 years ago

Read 2 more answers

A washing machine sits on the floor. How can you increase the force of friction on the washing machine without changing the surf

Vladimir79 [104]

Answer:

Push the washing machine harder onto the surface it sits upon, increasing friction between the two.

Explanation:

3 0

3 years ago

Earth has a surface area of 197 million square miles. Convert this area into each of the following units.

slamgirl [31]

Answers:

a) $510,225,121.4 km^{2}$

We know the Earth's surface area in square miles is:

$197000000 mi^{2}$

On the other hand, we know $1 mi=1.60934 km$ .

Then:

$197000000 mi^{2} \frac{(1.60934 km)^{2}}{1 mi^{2}}=510,225,121.4 km^{2}$

b) $510.225 Mm^{2}$

In this part, we can work with the obtained value in part a:

$510,225,121.4 km^{2}$

And knowing $1 km=0.001 Mm$

Hence:

$510,225,121.4 km^{2} \frac{(0.001 Mm)^{2}}{1 km^{2}}=510.225 Mm^{2}$

c) $5.1022(10)^{16} dm^{2}$

Knowing $1 Mm=10^{7} dm$ :

$510.225 Mm^{2} \frac{(10^{7} dm)^{2}}{1 Mm^{2}}=5.1022(10)^{16} dm^{2}$

7 0

3 years ago

I need actual help, not just the answers. I need explanations and formulas please.

yaroslaw [1]

Using newton's law of gravity on a 1kg mass near the star. G is newton's grav constant. g is acceleration of grav at starGMstar/r^2 = gstar

3 0

3 years ago

Quantity A of an ideal gas is at absolute temperature T, and a second quantity B of the same gas is at absolute temperature 2T.

Ira Lisetskai [31]

Answer: Yes both gases would have the same entropy.

Explanation:

The formula for the change in the entropy is as follows,

$\Delta S = \frac{Q}{T}$

Here, \Delta S is the change in the entropy, Q is the heat transfer and T is the temperature.

If the temperature of the system increases then there will be increase in the entropy as the randomness of the system increases.

In the given problem, if the both gases were initially at the same absolute temperature. Then there will be same entropy change in both gases.

Therefore, yes both gases would have the same entropy.

5 0

3 years ago