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kondor19780726 [428]
3 years ago
6

90Th234 What element atom is formed when the thorium nucleus is оруулах-decomposed?​

Physics
1 answer:
Archy [21]3 years ago
8 0

This question is from course hero.

So better check this question!

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Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air
frosja888 [35]

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

f=\frac{v}{\lambda}

where v is the wave's speed and \lambda is the wavelength.

Applying the formula:

- In air, the frequency of the wave is:

f=\frac{400 m/s}{2 m}=200 Hz

- underwater, the frequency of the wave is:

f=\frac{1600 m/s}{8 m}=200 Hz

So, the frequency has not changed.

3 0
3 years ago
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Which of the fluids below would produce the highest pressure at the bottom of a tank for the same fluid depth?
marishachu [46]
The answer is  a property of density. The higher the density, the higher the pressure at the bottom. 

Pressure = mass / Area. So given that the 4 samples occupy the same area at the bottom, the mass is going to be the determining factor. Per given volume, mercury has the largest mass. The answer is A
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3 years ago
Which of the following situations would cause the greatest decrease in the motion of molecules in a system?
Alina [70]

A. is the right answer since work is negative and Q which is heat in negative also

7 0
3 years ago
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a vehicle travels at a constant speed of 65 mph for 4 hours how far has this vehicle travelled in this time
Nostrana [21]
260 miles.................
3 0
3 years ago
a container of water is knocked off a 10.0 meter high ledge with a horizontal velocity of 1.00 meters/second. calculate the time
Evgen [1.6K]

Answer:

1.43 s

Explanation:

The time it takes for the container to reach the ground is determined only by the vertical motion of the container, which is a free-fall motion, so a uniformly accelerated motion with a constant acceleration of g=9.8 m/s^2 towards the ground.

The vertical distance covered by an object in free fall is given by

S=ut + \frac{1}{2}at^2

where

u = 0 is the initial vertical speed

t is the time

a= g = 9.8 m/s^2 is the acceleration

since u=0, it can be rewritten as

S=\frac{1}{2}gt^2

And substituting S=10.0 m, we can solve for t, to find the duration of the fall:

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(10.0 m)}{9.8 m/s^2}}=1.43 s

3 0
4 years ago
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