Question

To understand the meaning of the variables in Gauss's law, and the conditions under which the law is applicable. Gauss's law is usually writtenΦE=∫ E.dA =qencl/ϵ0where ϵ0=8.85×10^−12C^2/(N⋅m^2) is the permittivity of vacuum.How should the integral in Gauss's law be evaluated?

Answer 1

Answer:

Over a closed surface

Explanation:

Gauss's law: It states that the total electric flux passing through the closed surface is equal to $\frac{1}{\epsilon_0}$ times the total charge enclosed within the surface.

Mathematically representation :

Electric flux=$\phi=\oint E\cdot dA=\frac{q}{\epsilon_0}$

Where q=Total charge enclosed within surface

$\epsilon=8.85\times 10^{-12}C^2/Nm^2$=Permittivity  of vacuum

Therefore,the integral in Gauss's law should be evaluated over a closed surface.

Circle in the integration mean closed we can say that closed integral.