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Ket [755]
2 years ago
10

A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,

what is the flow rate through the artery? Assume that the temperature is 37°C and the viscosity of whole blood is 2.084 × 10-3 Pa·s.
Physics
1 answer:
levacccp [35]2 years ago
8 0

Answer:

7.69533\times 10^{-11}\ m^3/s

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius = 2.5\times 10^{-5}\ m

\eta = Viscosity of liquid = 2.084\times 10^{-3}\ Pas

l = Length of artery = 1.1\times 10^{-3}\ m

From Poiseuille's equation we have

Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s

The flow rate of blood is 7.69533\times 10^{-11}\ m^3/s

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