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mixer [17]
4 years ago
11

Hospital X-ray generators emit X-rays with wavelength of about 15.0 nanometers (nm), where 1nm=10−9m. What is the energy of a ph

oton of the X-rays? Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
Sergio [31]4 years ago
4 0

Answer:

E=1.32\times 10^{-17}\ J

Explanation:

Given that,

The wavelength of x ray, \lambda=15\ nm=15\times 10^{-9}\ m

We need to find the energy if a photon on the x-rays. The formula for the energy of the photon is given by :

E=\dfrac{hc}{\lambda}

E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{15\times 10^{-9}}

E=1.32\times 10^{-17}\ J

So, the energy of a photon of the X-rays is 1.32\times 10^{-17}\ J. Hence, this is the required solution.

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Which of the following is an example of distance equaling displacement?
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Answer:

D

Explanation:

The student had displaced their in the class when she left. The phone is what's displaced and student leaving equals distance.

3 0
3 years ago
A 95.0 kg satellite moves on a circular orbit around the Earth at the altitude h=1.20*103 km. Find: a) the gravitational force e
Natali5045456 [20]

Answer:

a) F = 660.576\,N, b) a_{c} = 6.953\,\frac{m}{s^{2}}, c) v \approx 7255.423\,\frac{m}{s}, \omega = 9.583\times 10^{-4}\,\frac{rad}{s}, d) T \approx 1.821\,h

Explanation:

a) The gravitational force exerted by the Earth on the satellite is:

F = G\cdot \frac{m\cdot M}{r^{2}}

F = \left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot \frac{(95\,kg)\cdot (5.972\times 10^{24}\,kg)}{(7.571\times 10^{6}\,m)^{2}}

F = 660.576\,N

b) The centripetal acceleration of the satellite is:

a_{c} = \frac{660.576\,N}{95\,kg}

a_{c} = 6.953\,\frac{m}{s^{2}}

c) The speed of the satellite is:

v = \sqrt{a_{c}\cdot R}

v = \sqrt{\left(6.953\,\frac{m}{s^{2}} \right)\cdot (7.571\times 10^{6}\,m)}

v \approx 7255.423\,\frac{m}{s}

Likewise, the angular speed is:

\omega = \frac{7255.423\,\frac{m}{s} }{7.571\times 10^{6}\,m}

\omega = 9.583\times 10^{-4}\,\frac{rad}{s}

d) The period of the satellite's rotation around the Earth is:

T = \frac{2\pi}{\left(9.583\times 10^{-4}\,\frac{rad}{s} \right)} \cdot \left(\frac{1\,hour}{3600\,s} \right)

T \approx 1.821\,h

6 0
3 years ago
One of the difficulties in studying mechanics is that many common words are used with highly specific technical meanings,among t
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Mnanan anaw anwkkww wjakana akkqna akaoaman akamakq

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3 years ago
A battery has some internal resistance. Can the potential difference across the terminals of the battery be equal to its emf.
yarga [219]

Answer:

yes, the potential difference across the terminals of the battery can be equal to its emf.

Explanation:

when the current in the battery is zero, meaning the current though, and hence the potential drop across the internal resistance is zero. This only happens when there is no load placed on the battery.

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4 years ago
Simon draws a diagram to illustrate the law of reflection.
Step2247 [10]

Answer:

Make the angle of reflection and the angle of incidence equal.

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The law of reflection states that at the point of incidence on a smooth surface, the angle of incidence is equal to the angle  of reflection, The incident ray, the normal and the reflected ray lie on the same plane.

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