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mixer [17]
3 years ago
11

Hospital X-ray generators emit X-rays with wavelength of about 15.0 nanometers (nm), where 1nm=10−9m. What is the energy of a ph

oton of the X-rays? Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

E=1.32\times 10^{-17}\ J

Explanation:

Given that,

The wavelength of x ray, \lambda=15\ nm=15\times 10^{-9}\ m

We need to find the energy if a photon on the x-rays. The formula for the energy of the photon is given by :

E=\dfrac{hc}{\lambda}

E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{15\times 10^{-9}}

E=1.32\times 10^{-17}\ J

So, the energy of a photon of the X-rays is 1.32\times 10^{-17}\ J. Hence, this is the required solution.

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In an elastic collision, two objects collide and return to their original positions with no loss of _________.
BARSIC [14]
No loss of kinetic energy! :)
6 0
3 years ago
A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 222 kg and it
inn [45]

Answer:

The buoyant force is 3778.8 N in upward.

Explanation:

Given that,

Mass of balloon = 222 Kg

Volume = 328 m³

Density of air = 1.20 kg/m³

Density of helium = 0.179 kg/m³

We need to calculate the buoyant force acting

Using formula of buoyant force

F_{b}=\rho_{air}\times V_{b}\times g

Where, \rho_{air} = density of air

V = Volume of balloon

g = acceleration due to gravity

Put the value into the formula

F_{b}=1.20\times321\times9.81

F_{b}=3778.8\ N

This buoyant force is in upward direction.

Hence, The buoyant force is 3778.8 N in upward.

4 0
3 years ago
The focal length of the lens of a simple digital camera is 40 mm, and it is originally focused on a person 25 m away. In what di
ss7ja [257]

Answer:

Explanation:

Here image distance is fixed .

In the first case if v be image distance

1 / v - 1 / -25 = 1 / .05

1 / v = 1 / .05 - 1 / 25

= 20 - .04 = 19.96

v = .0501 m = 5.01 cm

In the second case

u = 4 ,

1 / v - 1 / - 4 = 1 / .05

1 / v = 20 - 1 / 4 = 19.75

v = .0506 = 5.06 cm

So lens must be moved forward by 5.06 - 5.01 =  .05 cm ( away from film )

3 0
3 years ago
A torque of 0.77 N⋅m is applied to a bicycle wheel of radius 30 cm and mass 0.70 kg
Naddik [55]

Answer:

α = τ/I = 0.77 / (0.70(0.30²)) = 12.22222... = 12 rad/s²

Explanation:

4 0
3 years ago
Please help me solve all of them ( a, b, c and d ) thankiew !! <br> I’m also kind of in a rush
Sergio039 [100]

Answer:

a-

V= IR

9V = I ×( 12+6)

I = 9/ 18 A = 0.5 A

b

V=IR

240 = 6 A ×( 20 + R)

40 = 20 + R

R = 20 ohm

c

resultant resistance of the 2 parallel resistances= Ro

1/Ro = 1/ 5 + 1/ 20

1/Ro =( 20+5)/100

= 1/Ro = 1/4

Ro= 4 ohm

V=IR

V = 2A × ( 1+ 4 OHM)

V = 10V

d

equivalent resistance = Ro

1/Ro = 1/(2+8) + 1/(5+5)

1/Ro = 1/10 +1/10

2/10 = 1/ Ro

Ro= 10/2 = 5 ohm

V = IR

12V = I × 5Ohm

I=2.4 A

6 0
2 years ago
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