Answer:
The buoyant force on the wood = 7.652 N
Explanation:
According to the principle of flotation, a body floats when the upthrust exerted upon it by the fluid n which it floats equals the weight of the body.
W = U ............... Equation.
Where W = weight of the wood, U = Upthrust or buoyant force.
Recall That,
Density = mass/volume
Mass = Density×volume
m = D×V........................ Equation 2
Where m = mass of the wood, V = Volume of the wood, D = Density of the wood.
But
Volume of a cube = a³
V = a³ where a = length of the cube.
V = 10³ = 1000 cm³.
Given: V = 1000 cm³ D = 0.780 g/cm³
Substituting these values into equation 2,
m = 1000(0.780)
m = 780 g
m = 0.78 kg.
But W = mg
Where m = 0.78 kg, g = 9.81 m/s²
W = 0.78(9.81)
W = 7.652 N.
Since W = U = 7.652 N.
U = 7.652 N
Therefore the buoyant force on the wood =7.652 N
