The answer I believe is c
Explanation
During the day when temperatures are higher, the snow melts and water enters the cracks in the rock. When the temperature drops below 0°C the water in the crack freezes and expands by about 9 per cent. This makes the crack larger.
Answer:
![a=3125000 m/s^2\\a=3.125*10^6 m/s^2](https://tex.z-dn.net/?f=a%3D3125000%20m%2Fs%5E2%5C%5Ca%3D3.125%2A10%5E6%20m%2Fs%5E2)
Acceleration, in m/s, of such a rock fragment = ![3.125*10^6m/s^2](https://tex.z-dn.net/?f=3.125%2A10%5E6m%2Fs%5E2)
Explanation:
According to Newton's Third Equation of motion
![V_f^2-V_i^2=2as](https://tex.z-dn.net/?f=V_f%5E2-V_i%5E2%3D2as)
Where:
is the final velocity
is the initial velocity
a is the acceleration
s is the distance
In our case:
![V_f=V_{escape}, V_i=0,s=4 m](https://tex.z-dn.net/?f=V_f%3DV_%7Bescape%7D%2C%20%20V_i%3D0%2Cs%3D4%20m)
So Equation will become:
![V_{escape}^2-V_i^2=2as\\V_{escape}^2-0=2as\\V_{escape}^2=2as\\a=\frac{V_{escape}^2}{2s}\\a=\frac{(5*10^3m)^2}{2*4}\\a=3125000 m/s^2\\a=3.125*10^6 m/s^2](https://tex.z-dn.net/?f=V_%7Bescape%7D%5E2-V_i%5E2%3D2as%5C%5CV_%7Bescape%7D%5E2-0%3D2as%5C%5CV_%7Bescape%7D%5E2%3D2as%5C%5Ca%3D%5Cfrac%7BV_%7Bescape%7D%5E2%7D%7B2s%7D%5C%5Ca%3D%5Cfrac%7B%285%2A10%5E3m%29%5E2%7D%7B2%2A4%7D%5C%5Ca%3D3125000%20m%2Fs%5E2%5C%5Ca%3D3.125%2A10%5E6%20m%2Fs%5E2)
Acceleration, in m/s, of such a rock fragment = ![3.125*10^6m/s^2](https://tex.z-dn.net/?f=3.125%2A10%5E6m%2Fs%5E2)
Answer:
Explanation:
To find the direction of this vector we need o find the angle that has a tangent of the y-component over the x-component:
but since we are in Q2 we have to add 180 degrees to that angle giving us 165.5 degrees
Explanation:
It is given that,
Mass of Millersburg Ferry, m = 13000 kg
Velocity, v = 11 m/s
Applied force, F = 10⁶ N
Time period, t = 20 seconds
(a) Impulse is given by the product of force and time taken i.e.
![J=F.\Delta t](https://tex.z-dn.net/?f=J%3DF.%5CDelta%20t)
![J=10^6\ N\times 20\ s](https://tex.z-dn.net/?f=J%3D10%5E6%5C%20N%5Ctimes%2020%5C%20s)
![J=2\times 10^7\ N-s](https://tex.z-dn.net/?f=J%3D2%5Ctimes%2010%5E7%5C%20N-s)
(b) Impulse is also given by the change in momentum i.e.
![J=\Delta p=p_f-p_i](https://tex.z-dn.net/?f=J%3D%5CDelta%20p%3Dp_f-p_i)
![J=p_f-p_i](https://tex.z-dn.net/?f=J%3Dp_f-p_i)
![p_f=J+p_i](https://tex.z-dn.net/?f=p_f%3DJ%2Bp_i)
![p_f=2\times 10^7\ N-s+13000\ kg\times 11\ m/s](https://tex.z-dn.net/?f=p_f%3D2%5Ctimes%2010%5E7%5C%20N-s%2B13000%5C%20kg%5Ctimes%2011%5C%20m%2Fs)
![p_f=20143000\ kg-m/s](https://tex.z-dn.net/?f=p_f%3D20143000%5C%20kg-m%2Fs)
(c) For new velocity,
![v_f=\dfrac{p_f}{m}](https://tex.z-dn.net/?f=v_f%3D%5Cdfrac%7Bp_f%7D%7Bm%7D)
![v_f=\dfrac{20143000\ kg-m/s}{13000\ kg}](https://tex.z-dn.net/?f=v_f%3D%5Cdfrac%7B20143000%5C%20kg-m%2Fs%7D%7B13000%5C%20kg%7D)
![v_f=1549.46\ m/s](https://tex.z-dn.net/?f=v_f%3D1549.46%5C%20m%2Fs)
Hence, this is the required solution.
Answer:multiplying will give us 7 significant figures and addition will give us 3 significant figures
Explanation:
After multiplying the two numbers they resulting value will give a value in its 4 decimal places because both given values are in 2 decimal places. The 4 dp is gotten by the addition of the decimal places of both given numbers (2+2) and
The result of its addition will give us a value in its 1dp and 3 significant figures since the addition of 23.68 and 4.12 will give us 27.8