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jolli1 [7]
3 years ago
8

Matter is defined as anything that has weight and takes up space.

Physics
1 answer:
serg [7]3 years ago
5 0

Answer:

true matter takes up space and is anything that is around us

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Your friend is trying to construct a clock for a craft show and asks you for some advice. She has decided to construct the clock
Anastasy [175]

Answer:

The period of the pendulum is  T  =  1.68 \  sec

Explanation:

The diagram illustrating this setup is shown on the first uploaded image

From the question we are told that

     The length of the rod is L =  80 \ cm

       The diameter of the ring is d = 10 \ cm

       The distance of the hole from the one end  D =  15cm

From the diagram we see that point A is the center of the brass ring

 So the length from the axis of  rotation is mathematically evaluated as

          AP = 80 + 10 -5 -15  

          AP =  70 \ cm =  \frac{70}{100}  =  0.7 \ m

Now the period of the pendulum is mathematically represented as

             T  = 2 \pi  \sqrt{\frac{AP}{g} }

             T  =  2 \pi \sqrt{\frac{0.7}{9.8 } }

             T  =  1.68 \  sec

     

     

     

4 0
3 years ago
How are density and buoyancy related to each other?
goblinko [34]

Answer:

Buoyant force is directly proportional to the density of the fluid in which an object is immersed. Buoyancy is the tendency to rise or float in a fluid. The upward force exerted on objects submerged in fluids is called the buoyant force. where ρ is the density, V is the volume, and m is the mass of the displaced fluid.

Explanation:

3 0
3 years ago
Read 2 more answers
............................................................??????????????
den301095 [7]

Answer:

I_{1} = 0.7 A, I_{2} = 1.3 A and ε = 7.4 V

Explanation:

From the given circuit, applying Kirchhoff's rule;

Ammeter reading, I_{0} = 2 A

⇒    I_{0} = I_{1} + I_{2} = 2 A

Dividing the circuit to loops 1 and 2.

a. From loop 1,

15 + 7I_{1} - 5I_{0} = 0

15 + 7I_{1} - 10 = 0    (since I_{0} = 2 A)

7I_{1} - 5 = 0

I_{1} = 0.7 A

But,  I_{0} = I_{1} + I_{2}

⇒      2 = 0.7 + I_{2}

        I_{2} = 1.3 A

b. From loop 2,

ε + 2I_{2} - 5I_{0} = 0

ε + 2I_{2} - 10 = 0

ε + 2.6 - 10 = 0

ε - 7.4 = 0

ε = 7.4 V

Therefore, I_{1} = 0.7 A, I_{2} = 1.3 A and ε = 7.4 V.

8 0
3 years ago
What is the planet's rotational speed from slowest to fastest?​
larisa86 [58]

Answer:

Jupiter is the fastest whereas Venus is the slowest

5 0
2 years ago
An object's distance from a converging lens is 3.78 times the focal length. a) Determine the location of the image. Express the
Romashka-Z-Leto [24]

Answer:

a) v=1.36f

b)m=.36

c) real

d) Inverted

Explanation:

a)

In this question we have given,

object distance from converging lens,u=-3.78f

focal length of converging lens,=f

we have to find location of image,v=?

and magnification,m=?

we know that u, v and f are related by following formula

\frac{1}{f} =\frac{1}{v}- \frac{1}{u}.............(1)

put values of f u in equation (1)

we got,

\frac{1}{f} =\frac{1}{v}- \frac{1}{-3.78f}

\frac{1}{f}-\frac{1}{3.78f} =\frac{1}{v}

\frac{2.78}{3.78f} =\frac{1}{v}

or

v=1.36f

b) Magnification, m=\frac{v}{u} \\m=\frac{1.36f}{3.78f}\\m=.36

c)

Here the object is located further away from the lens than the focal point therefore image is real image and inverted.

d) image is inverted

7 0
3 years ago
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