On a 10 kg cart (shown below), the cart is brought up to speed with 50N of force for 7m, horizontally. At this point (A), the ca
rt begins to experience an average frictional force of 15N throughout the ride.
Find:
a) The total energy at (A)
b) The velocity at (B)
c) The velocity at (C)
d) Can the cart make it to Point (D)? Why or why not?
Find:
a) The total energy at (A)
b) The velocity at (B)
c) The velocity at (C)
d) Can the cart make it to Point (D)? Why or why not?
1 answer:
You might be interested in
Answer:
Velocity = 0.4762 m/s
Explanation:
Given the details for the simple harmonic motion from the question as:
Angular frequency, ω = 12 rad/s
Amplitude, A = 0.060 m
Displacement, y = 0.045 m
The initial Energy = U = (1/2) kA²
where A is the amplitude and k is the spring constant.
The final energy is potential and kinetic energy
K + U = (1/2) mv² + (1/2) kx²
where x is the displacement
m is the mass of the object
v is the speed of the object
Since energy is conservative. So, the final and initial energies are equal as:
(1/2) k A² = (1/2) m v² + (1/2) kx²
Using, ω² = k/m, we get:
Velocity:
<u>Velocity = 0.4762 m/s</u>