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choli [55]
3 years ago
9

Which quantity measures the maximum distance an object on a spring moves from the equilibrium position during oscillation?

Physics
2 answers:
nirvana33 [79]3 years ago
7 0

Answer:

amplitude

Explanation:

The maximum distance from the mean position or the equilibrium position on its either side of an oscillating body is called its amplitude.

nasty-shy [4]3 years ago
5 0
The appropriate response is amplitude. A measure of its change over a solitary period. There are different meanings of plentifulness, which are all elements of the extent of the distinction between the variable's outrageous qualities. In more seasoned writings, the stage is now and again called the adequacy.
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1. A block of aluminum occupies
Anvisha [2.4K]

Answer:

2700g/L

Explanation:

D=m/v

40.5g/0.015L

7 0
3 years ago
A 49-year-old female was referred for mammography, but she is very apprehensive after reading about the risk of ionizing radiati
SOVA2 [1]

Answer:

Mammography is the process in which low energy radiations are used to diagnose and screening. The purpose of this process is the early detection of the breast cancer. These low energy radiations may have some risks like damaging and burning of cells.  

In the current scenario, woman is apprehensive because she has read about the risks of using ionizing radiations. The radiographer should tell her the benefits of the mammography will outweigh its potential consequences. Screening, for instance, will let her know if she is suffering from breast cancer. Cancer is very dangerous disease as compare to very small burning.

In this way radiographer should handle the situation.

4 0
3 years ago
You have a bowling ball with a mass of 4kg. You throw it with an acceleration of 10 m/s/s. With how much force will it hit the p
Eddi Din [679]

Answer:

<h3>The answer is 40 N</h3>

Explanation:

The force acting on an object can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 4 kg

acceleration = 10 m/s²

So we have

force = 4 × 10

We have the final answer as

<h3>40 N</h3>

Hope this helps you

6 0
3 years ago
A horizontal 2.00\ m2.00 m long, 5.00\ kg5.00 kg uniform beam that lies along the east-west direction is acted on by two forces.
Sunny_sXe [5.5K]

Answer: 240\ rad/s^2

Explanation:

Given

Length of beam l=2\ m

mass of beam m=5\ kg

Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude

\tau =F\times l=200\times 2=400\ N.m

Also, the beam starts rotating about its center

So, the moment of inertia of the beam is

I=\dfrac{ml^2}{12}=\dfrac{5\times 2^2}{12}\\\\I=\dfrac{5}{3}\ kg.m^2

Torque is the product of moment of inertia and angular acceleration

\Rightarrow \tau=I\alpha\\\\\Rightarrow 400=\dfrac{5}{3}\times \alpha\\\\\Rightarrow \alpha =240\ rad/s^2

7 0
3 years ago
Please help
iVinArrow [24]
Answer is 4,400,000 kg • m/s
4 0
3 years ago
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