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3 years ago

Which quantity measures the maximum distance an object on a spring moves from the equilibrium position during oscillation?

Physics

2 answers:

nirvana33 [79]3 years ago

7 0

Answer:

amplitude

Explanation:

The maximum distance from the mean position or the equilibrium position on its either side of an oscillating body is called its amplitude.

nasty-shy [4]3 years ago

5 0

The appropriate response is amplitude. A measure of its change over a solitary period. There are different meanings of plentifulness, which are all elements of the extent of the distinction between the variable's outrageous qualities. In more seasoned writings, the stage is now and again called the adequacy.

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Before a star is born, the matter that will become the star exists as a

vazorg [7]

Answer:

The answer is D

Explanation:

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What is the dependent variable in this

Whitepunk [10]

Answer:

"the plants had already started growing."

Explanation:

I think this is the answer because the definition of a dependent variable is the variable that is being affected by the change. Since the plants had already started growing BECAUSE of "They ran out of the farmer's compost, so

some of the plants received that compost

when the seeds were planted and other

plants got hardware store compost after

the plants had already started growing."

Sorry if I am wrong, I am just a 4th grader, pls don't hate on me, I am just trying to help :)

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3 years ago

A meter stick is held vertically above your hand, with the lower end between your thumb and first finger. On seeing the meter st

inessss [21]

Answer:

$t=0.193s$

Explanation:

What is said is that the meter fell d=18.3cm=0.183m under the action of gravity. We can use the formula for accelerated motion:

$d=v_0t+\frac{at^2}{2}$

Since it departed from rest it will mean that:

$d=\frac{at^2}{2}$

So our time will be:

$t=\sqrt{\frac{2d}{a}}$

Which for our values is:

$t=\sqrt{\frac{2(0.183m)}{(9.81m/s^2)}}=0.193s$

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3 years ago

Joe is attempting to ramp his bicycle over a row of burning tires. If the ramp has a launch angle of 20 degrees, and Joe can ped

Luden [163]

Answer is 6 tires.

This is a projectile question.

First make sure units are consistent - express speed in m/s.

20 km/h = 20000m / 3600 s = 5.56 m/s

Assume the takeoff point of the ramp is at ground level (height, h, = 0m). We need to determine how long Joe is in the air, and use that time to calculate the horizontal distance he traveled.

Joe is traveling 5.56 m/s on a ramp angled at 20 degrees. There are vertical and horizontal components to his speed:

Vertical speed = 5.56sin20 = 1.90 m/s
Horizontal speed = 5.56cos20 = 5.22 m/s

An easy way to proceed is to calculate the time it takes for Joe’s vertical speed to reach 0m/s - this represents the time when Joe is at his maximum height and is therefore halfway through the trip. Double whatever time this is to find the total time of the trip. Remember he is decelerating due to gravity:

Time to peak:
a = Δv / Δt
-9.8 = -1.9 / Δt
Δt = 0.19s

Total trip time:
0.19 x 2 = 0.38s

Now that we have the total tome Joe is in the air, we can find the horizontal distance he traveled:

v = d / t
5.22 = d / 0.38
d = 1.98m

Now divide this total distance by the length of an individual tire to find the number of tires he will clear:

1.98 / 0.3 = 6.6 tires

Therefore he can jump 6 tires safely (he will land in the middle of the 7th tire).

Lots of steps I know but just try to think of the situation and keep track of the vertical and horizontal things!

4 0

3 years ago