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ki77a [65]
3 years ago
12

If you run a complete loop around an outdoor track of length 400 m in 100 s, find your(a) average velocity and (b) average speed

. *
Physics
1 answer:
laila [671]3 years ago
5 0

Answer:

a) 0 m/s

b) 4 m/s

Explanation:

The average velocity would end up being 0 because it is displacement over time and the displacement here is 0. However, speed is total distance over time which here is 400/100 so it is 4.

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An object accelerates 3.0 m/s2 when a force of 6.0 N is applied to it. What is the mass of the object?
makvit [3.9K]

Answer:

<h2>2 kg</h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{6}{3}  \\

We have the final answer as

<h3>2 kg</h3>

Hope this helps you

5 0
2 years ago
How far is tau hercules in light years from earth?
Nady [450]
Hipparcos estimated its distance at roughly 96 parsecs from Earth, or 310 ± 20 light years away.
8 0
3 years ago
A 2.3 m long wire weighing 0.075 N/m is suspended directly above an infinitely straight wire. The top wire carries a current of
ZanzabumX [31]

Answer:

Explanation:

Magnetic field near current carrying wire

= \frac{\mu_0}{4\pi} \frac{2i}{r}

i is current , r is distance from wire

B =  10⁻⁷ x \frac{2\times49}{r}

force on second wire per unit length

B I L , I is current in second wire , L is length of wire

=  10⁻⁷ x \frac{2\times49}{r} x 33 x 1

= 3234 x \frac{10^{-7}}{r}

This should balance weight of second wire per unit length

3234 x \frac{10^{-7}}{r} = .075

r = \frac{3234}{.075} x 10⁻⁷

= .0043 m

= .43 cm .

5 0
3 years ago
Pascal has 96 miles remaining to complete his cycling trip. If he reduced his current speed by 4 miles per hour, the remainder o
Verdich [7]

Answer:

V = 20 miles /sec

Explanation:

We have remaining distance   =  d  = 96 miles

Lets call  Pascal velocity  V in miles per hour

Now if he increases his velocity by  50 % (equivalent to multiply by 1.5 ) he will need a time t₁ to arrive then as V = d/t

1.5* V  = d/ t₁      ⇒   1.5 * V  =  96 /t₁

And in the case of reducing his velocity

(V / 4) = d/ (t₁ + 16 )     ⇒  V * (t₁ + 16 ) = 4*d     ⇒ V*t₁ + 16*V = 384

So we a 2 equation system with two uknown variables

1.5*V = 96/t₁      (1)

V*t₁  + 16*V = 384     (2)

We solve  from equation    (1)      t₁  = 64/V

And by substitution   in equation (2)

V * (64/V) + 16* V = 384

64  + 16 *V  = 384         ⇒   16*V = 320      ⇒  V= 320/16

V = 20 miles /sec

6 0
3 years ago
What is the mass of an object if a force of 34 N produces an acceleration of 4.0 m/s squared​
mrs_skeptik [129]

Answer:

8.5 kg

Explanation:

F = ma

34 N = m(4.0m/s^2)

m = 8.5 kg

6 0
2 years ago
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