1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lys-0071 [83]
3 years ago
11

Gravity is greater when there is

Physics
2 answers:
emmainna [20.7K]3 years ago
6 0
The correct answer is C. more mass and less distance between two objects.
Jobisdone [24]3 years ago
4 0
Choice-C is always true. Choices B and D may be true depending on the masses and distances. Choice-A is never true.
You might be interested in
An airplane flies at 150 km/hr. (a) The airplane is towing a banner that is b = 0.8 m tall and l = 25 m long. If the drag coef-
maw [93]

Answer:

  1. Power requirement <u>P</u> for the banner is found to be  30.62 W
  2. Power requirement <u>P</u> for the solid flat plate is found to be 653.225 W
  3. Answer for part(c) is explained below in the explanation section and can be summarized as: The main difference between the drags and power requirements of the two objects of same size was due to their significantly different drag-coefficients. The <em>Cd </em>for banner was given, whereas the <em>Cd </em>for a flat plate is generally found to be around <em><u>1.28</u></em><em> </em>which is the value we used in our calculations that resulted in a huge increase of power to tow the flat plate
  4. Power requirement <u>P</u> for the smooth spherical balloon was found to be 40.08 W

Explanation:

First of all we will establish variables and equations known that are known to us to solve this question. Since we are given the velocity of the airplane:

  1. v = velocity of airplane i.e. 150 km/hr. To convert it into m/s we will divide it by 3.6 which gives us 41.66 m/s
  2. The density of air at s.t.p (standard temperature pressure) is given as d = 1.225 kg / m^3
  3. The power can be determined this equation: P = F . v, where F represents <em>the drag-force</em> that we will need to determine and v represents the<em> velocity of the airplane</em>
  4. The equation to determine drag-force is: F = 1/2 * d *  C_d * A

In the drag-force equation Cd represents the c<em>o-efficient of drag</em> and A represents the <em>frontal area of the banner/plate/balloon (the object being towed)</em>

Frontal area A of the banner is : 25 x 0.8 = 20 m^2

<u>Part a)</u> We will plug in in the values of Cd, d, A in the drag-force equation i.e. Fd = <em>1/2 * 0.06* 1.225 * 20</em> = 0.735 N. Now to find the power P we will use P = F . v i.e.<em> 0.735 * 41.66</em> = <u><em>30.62 W</em></u>

<em></em>

<u>Part b) </u>For this part the only thing that has fundamentally changed is the drag-coefficient Cd since it's now of a solid flat plate and not a banner. The drag-coefficient of a flat plate is approximately given as : Cd_fp = 1.28

Now we will plug-in our values into the same equations as above to determine drag-force and then power. i.e. Fd = <em>1/2 * 1.28 * 1.225 * 20</em> = 15.68 N. Using Fd to determine power, P = 15.68 * 41.66 = <u><em>653.225 W</em></u>

<u><em></em></u>

<u>Part c)</u> The main reason for such a huge power difference between two objects of same size was due to their differing drag-coefficients, as drag-coefficients are generally large for objects that are not of a streamlined shape and leave a large wake (a zone of low air pressure behind them). The flat plate being solid had a large Cd where as the banner had a considerably low Cd and therefore a much lower power consumption

<u>Part d)</u> The power of a smooth sphere can be calculated in the same manner as the above two. We just have to look up the Cd of a smooth sphere which is found to be around 0.5 i.e. Cd_s = 0.5. Area of sphere A is given as : <em>pi* r^2 (r = d / 2).</em> Now using the same method as above:

Fd = 1/2 * 0.5 * 3.14 * 1.225 = 0.962 N

P = 0.962 * 41.66 = <u><em>40.08 W</em></u>

4 0
3 years ago
An astronaut on Earth notes that in her soft drink an ice cube floats with 9/10 of its volume submerged. If she were instead in
riadik2000 [5.3K]

Answer:

B) with 9/10 submerged

Explanation:

m = mass of ice cube

\rho = density of soft drink

V = Volume of soft drink displaced

ice cube floats in the soft drink when the force of buoyancy on it balances its weight. Force of buoyancy acting on the cube in upward direction is same as the weight of the soft drink displaced. hence we can write

weight of ice cube = weight of soft drink displaced

mg = \rho V g

m = \rho V

we see that the acceleration due to gravity cancel out both side and hence it does affect as astronaut is on earth on in a lunar module.

8 0
3 years ago
Read 2 more answers
Give you point but please i need help in physcis
Anastasy [175]

Explanation:

Hi

Hi

Hi

Hi

BRAINILIEST PLEASE

7 0
3 years ago
Which level of protein structure is formed by the weak bonds between oxygen and hydrogen atoms within the polypeptide backbone.
vredina [299]

Answer:

Secondary structure

The secondary structure arises from the hydrogen bonds formed between atoms of the polypeptide backbone. The hydrogen bonds form between the partially negative oxygen atom and the partially positive nitrogen atom

8 0
2 years ago
An elevator filled with passengers has a mass of 1603 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 f
Galina-37 [17]

Answer:

T = 17649.03 N = 17.65 KN

Explanation:

The tension in the cable must be equal to the apparent weight of the passenger. For upward acceleration:

T = W_A = m(g+a)\\

where,

T = Tension in cable = ?

W_A = Apparent weight

m = mass = 1603 kg

g = acceleration due to gravity = 9.81 m/s²

a = acceleration of elevator = 1.2 m/s²

Therefore,

T = (1603\ kg)(9.81\ m/s^2+1.2\ m/s^2)\\\\

<u>T = 17649.03 N = 17.65 KN</u>

8 0
2 years ago
Other questions:
  • A block of mass m=0.4 kg starts from rest and slides down a frictionless ramp, before hitting a spring of spring constant k = 30
    6·1 answer
  • A turnip is dropped from a height of 70 meters. How long does it take to hit the ground?
    14·1 answer
  • 3. How does the vapor pressure of water at 10°C compare with its vapor pressure at 50°C? The vapor pressure of water is lower at
    11·2 answers
  • Consider a cylinder initially filled with 9.33 10-4 m3 of ideal gas at atmospheric pressure. An external force is applied to slo
    14·1 answer
  • What are laws of newton
    9·2 answers
  • Arrange the steps in order to describe what happens to a gas when it cools
    6·1 answer
  • A system uses 2,380 J of energy to do work as 12,900 J of heat are added to the system.
    9·1 answer
  • Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. Through what angle
    6·1 answer
  • When conducting objects (such as metals) are connected for a brief time, charge can be made to flow quite easily from one to the
    13·1 answer
  • Tapping into this energy source could provide at least 10 times the energy that can be obtained from the nation’s known coal res
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!