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goldenfox [79]
3 years ago
14

True or False

Chemistry
1 answer:
alexdok [17]3 years ago
5 0
1. True 2. False 3.false 4. False 5. True
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Carl adds a 6.70-gram cube of ice at 0.0°C to cool a glass of juice, As the ice melts, the temperature of the newly melted water
raketka [301]

Answer:

2,950

joules.

Explanation:

The units don’t need conversion, and the formula doesn’t need changing.

First, determine the energy required to melt the ice:

Q = mHf

Q = 6.70 g × 334

Q = 2,240 J

Next, determine the energy needed to raise the temperature of the newly melted water:

Q = mCΔT

Q = 6.70 g × 4.186 × (25.4°C – 0.0°C)

Q = 712 J

Now, add the energy values. Express the answer to 3 significant figures:

2,240 J + 712 J = 2,950 J.

7 0
3 years ago
Which idea did isaac newtons experiments with light supports?
notsponge [240]

Answer:

The Newton experiment with light supports the particle nature of the light. Option C is correct. Light is made of particles because it travels only in a straight path. According to his experiments, he concluded that that light is made up of particles and they travel in straight lines

Explanation:

4 0
3 years ago
Read 2 more answers
A sample of nitric acid has a mass of 8.2g. It is dissolved in 1L of water. A 25mL aliquot of this acid is titrated with NaOH. T
AveGali [126]

Answer:

18.075 mL of NaOH solution was added to achieve neutralization

Explanation:

First, let's formulate the chemical reaction between nitric acid and sodium hydroxide:

NaOH + HNO3 → NaNO3 + H2O

From this balanced equation we know that 1 mole of NaOH reacts with 1 mole of HNO3 to achieve neutralization. Let's calculate how many moles we have in the 25 mL aliquot to be titrated:

63.01 g of HNO3 ----- 1 mole

8.2 g of HNO3 ----- x = (8.2 g × 1 mole)/63.01 g = 0.13014 moles of HNO3

So far we added 8.2 grams of nitric acid (0.13014 moles) in 1 L of water.

1000 mL solution ---- 0.13014 moles of HNO3

25 mL (aliquot) ---- x = (25 mL× 0.13014 moles)/1000 mL = 0.0032535 moles

So, we now know that in the 25 mL aliquot to be titrated we have 0.0032535 moles of HNO3. As we stated before, 1 mole of NaOH will react with 1 mole of HNO3, hence 0.0032535 moles of HNO3 have to react with 0.0032535 moles of NaOH to achieve neutralization. Let's calculate then, in which volume of the given NaOH solution we have 0.0032535 moles:

0.18 moles of NaOH ----- 1000 mL Solution

0.0032535 moles---- x=(0.0032535moles×1000 mL)/0.18 moles = 18.075mL

As we can see, we need 18.075 mL of a 0.18 M NaOH solution to titrate a 25 mL aliquot of the prepared HNO3 solution.

4 0
3 years ago
Which is the best example of how electromagnetic energy is used in everyday life?
Sever21 [200]
A patient receiving an X-ray in a hospital
4 0
3 years ago
Dl water will test<br> _________for protein?
Ann [662]

Answer:

Total protein range. The normal range for total protein is between 6 and 8.3 grams per deciliter (g/dL). This range may vary slightly among laboratories.

Explanation:

5 0
3 years ago
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