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OleMash [197]
2 years ago
13

In a double bond, two atoms share a total of _____ electrons. a two b three c four d six

Chemistry
1 answer:
MissTica2 years ago
3 0

Answer:

C: 4

Explanation:

In every single covalent bond, each atom shares one electron. 1 + 1 = 2. A double bond is just two bonds so, 2 x 2 = 4.

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Uranium has an atomic weight of 238 amu.
shepuryov [24]

Answer:

U= 238g/mol

U2O5= 556g/mol

Explanation:

Since U= 238

O=16

U3O5= 2(238)+3(16)=556g/mol

4 0
3 years ago
How to calculate moles
blondinia [14]

Explanation:

First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.

For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.

8 0
3 years ago
Read 2 more answers
What are some physical means of separating something?
Alika [10]
Mixtures come in many forms and phases. Most of them can be separated, and the kind of separation method depends on the kind of mixture it is. Below are some common separation methods:
3 0
3 years ago
What is the world's most common acid<br> and also the world's most common base?
Ray Of Light [21]

Answer:

Thus, as both an amphoteric compound and the most common liquid on Earth, it follows that water is both the most common acid as well as the most common base on planet Earth

4 0
3 years ago
Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40
devlian [24]

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

ΔT =  20°C

48 J = 12 g×c×20°C

48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

6 0
2 years ago
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