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NNADVOKAT [17]
3 years ago
7

Using the square-bracket notation, express the concentration of ions in a solution that is 0.811 M in aluminum sulfate [Al2(SO4)

3].
[Al^3+] = ____ M

[SO4^2−] = ____ M
Chemistry
1 answer:
Vadim26 [7]3 years ago
7 0

Answer:

[Al³⁺] = 1.62 M

[SO₄²⁻] = 2.43 M

Explanation:

Step 1: Given data

Molar concentration of Al₂(SO₄)₃: 0.811 M

Step 2: Write the reaction for the ionization of Al₂(SO₄)₃

Al₂(SO₄)₃(aq) ⇒ 2 Al³⁺(aq) + 3 SO₄²⁻(aq)

Step 3: Calculate the molar concentration of Al³⁺

The molar ratio of Al₂(SO₄)₃ to Al³⁺ is 1:2. The molarity of Al³⁺ is 2/1 × 0.811 M = 1.62 M.

Step 4: Calculate the molar concentration of SO₄²⁻

The molar ratio of Al₂(SO₄)₃ to SO₄²⁻ is 1:3. The molarity of SO₄²⁻ is 3/1 × 0.811 M = 2.43 M

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Names: hydrogen atom, H-1, protium, ¹H

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3 years ago
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Type the correct answer in the box. Express your answer to three significant figures. Iron(II) chloride and sodium carbonate rea
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Answer:

The reaction can produce 287 grams of iron(II) carbonate

Explanation:

To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-

<em>Moles FeCl2:</em>

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<em>Mass FeCO3:</em>

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5 0
3 years ago
Can someone please tell me this answer​
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Answer:

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Answer:

Diluted solution

Explanation:

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Answer:

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Explanation:

In every chemical reaction, there is a limiting reactant and there is an excess reactant.

The limiting reactant determines the amount of product obtained. It is the reactant that produces a lesser amount of the product.

The excess reactant is known to be the reactant that produces a greater amount of the product.

The theoretical yield is calculated using the limiting reactant and is the amount of product predicted to be produced by the given reactants.

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