The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.
<h3>What is the electron dot diagram?</h3>
The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.
The electron dot diagram for the oxygen atom is drawn as follows:
- The number of valence electrons in oxygen atom is determined; valence electrons = 6
- The symbol for the oxygen atom is written
- The valence electrons are shown as dots around the symbol of the element.
In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.
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I have done some research as well as asking some friends. This is what I came up with. Not sure if it is 100% correct.
step = time after death
1. Livor Mortis = 20-30 minutes
2. Eyes film (cloud) = 2 hours
3. Rigor Mortis begins = 4-6 hours
4. Empty small intestines = 12 hours
5. Bloating = 3-5 days
6. Decay
Ammonium hydroxide aka ammonia is a colorless gas that smells awful.... ammonia contains nitrogen and hydrogen.... and also ammonia is used as a lifting gas, which means it cans be used to lift hot air balloons.... lol that was just a weird fact..... but have an amazing day/night and god bless u!
Answer:
2.04 x 10²⁴ molecules
Explanation:
Given parameters:
Mass of Be(OH)₂ = 145.5g
To calculate the number of molecules in this mass of Be(OH)₂ we follow the following steps:
>> Calculate the number of moles first using the formula below:
Number of moles = mass/molarmass
Since we have been given the mass, let us derive the molar mass of Be(OH)₂
Atomic mass of Be = 9g
O = 16g
H = 1g
Molar Mass = 9 + 2(16 + 1)
= 9 + 34
= 43g/mol
Number of moles = 145.5/43 = 3.38mol
>>> We know that a mole is the amount of substance that contains Avogadro’s number of particles. The particles can be atoms, molecules, particles etc. Therefore we use the expression below to determine the number of molecules in 3.38mol of Be(OH)₂:
Number of
molecules= number of moles x 6.02 x 10²³
Number of molecules= 3.38 x 6.02 x 10²³
= 20.37 x 10²³ molecules
= 2.04 x 10²⁴ molecules
The empirical formula is = C2H4O2
Molecular formula=C2H4O2
<h3>Calculation of
Molecular formula and empirical formula:-</h3>
Vinegar has three elements:
oxygen = 53.29%,
hydrogen = 6.70%,
and carbon = 40.01%.
We can create an equation for the total mass of vinegar with 'a' carbon atom,' b' hydrogen atom, and 'c' oxygen atoms using the molar masses of C, H, and O.
12*a + 1*b + 16*c = 60
We also know that C makes up 24 g/mol, or 40.01 percent, of the overall mass of 60 g/mol.
The formula contains two C atoms because each C atom has a molecular mass of 12 g/mol. You may determine that the formula contains 4 H and 2 O atoms by using the same reasoning for H and O.
The empirical formula is = C2H4O2
Molecular formula= (C2H4O2)n
(4 x 12 + 1 x 4 + 16 x 2)n = 60
(84)n = 60
n=60/84
n=0.71=1
Molecular formula=C2H4O2
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