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3 years ago

Calculate the number of joules needed to change 20.0 g of ice at 0.00 °C to liquid water at 42.8 °C

Chemistry

1 answer:

tigry1 [53]3 years ago

5 0

Answer:

7509.6j

Explanation:

I asked if the temperature of the ice but since it doesn't that means the temperature of the ice is at 0°c and latent heat of fusion [ML] will take place when it changes to water at 0°c also, then the temperature of the water rises to 10°c MCΘ will be used.

Now in the application, using the formula;

mL+MCΘ

Where;

m=20 L=334 M=4.148 Θ=10

Inputting the values we should have;

334×20+4.148×20×10

6680+829.6

7509.6j

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What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter

Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, $31.0^oC$

Explanation :

First we have to calculate the heat produced.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of $NaOH$ = 1.52 g

Molar mass of $NaOH$ = 40 g/mol

$\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole$

Now put all the given values in the above formula, we get:

$44.5kJ/mol=\frac{q}{0.038mol}$

$q=1.691kJ$

Now we have to calculate the final temperature of solution in the calorimeter.

$q=m\times c\times (T_2-T_1)$

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = $4.18J/g^oC$

$T_1$ = initial temperature = $20.1^oC$

$T_2$ = final temperature = ?

Now put all the given values in the above formula, we get:

$1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)$

$T_2=31.0^oC$

Thus, the final temperature of the solution in the calorimeter is, $31.0^oC$

4 0

3 years ago

1. What causes wind? *

Gelneren [198K]

Answer:

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Explanation:

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2 years ago

In 1901, Thomas Edison invented the nickel-iron battery. The following reaction takes place in the battery.

Sedaia [141]

Answer:

Explanation:

1 mole of Fe require 2 Moles of NiO(OH)

so for 4.25 mol of Fe and 6.70 mol of NiO(OH), Fe is the limiting reagent.

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4.25 moles will produce 4.25 moles of Fe(OH)2

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3 years ago

Determining wether the molecule is polar or non polar

Rainbow [258]

Answer:

1) polar

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3 years ago

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3 years ago