The formation of carbondioxide is given by equation as
C + O2 ----> CO2(g)
As per balanced equation one mole of carbondioxide is obtained from one mole of carbon
if 44 g of CO2 is formed it means it contains 12 g of carbon
if 1g of CO2 is formed it means it contains 12/44 g of carbon
if 0.528g of CO2 is formed it means it contains = 12 X 0.528 / 44 g of carbon
= 0.144g of carbon
Similarly for water
H2 + 0.5O2 ---> H2O
so one mole of water is obtained from one mole of H2
if 18g of water is formed it means 2g H2 is present
if 1g of water is formed it means 2/18 g of H2 is present
if 0.216g of water if formed it means 2 X 0.216 / 18g of H2 is present = 0.024g of Hydrogen
In glucose we have Carbon , Hydrogen and oxygen
As given the total mass of sample = 0.360g
Mass of carbon = 0.144 , moles of carbon = 0.144 / 12 = 0.012
Mass of hydrogen = 0.024 , moles of hydrogen = 0.024 /1 = 0.024
mass of oxygen = 0.360 - (0.144+0.024) = 0.192
Moles of oxygen = 0.192 / 16 = 0.012
So mole ratio of C : H : O = 0.012 : 0.024 : 0.012 = 1:2:1
Empirical formula = CH2O
