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goldfiish [28.3K]
2 years ago
9

Can someone please help!

Mathematics
1 answer:
Fudgin [204]2 years ago
3 0

Answer:

min f(x) = 3.95  (for x= 2.5)

Step-by-step explanation:

vertex (x) = 1/0,4 = 2,5

vertex (y) = 0.2(2.5)^2-2.5+5.2 = 3.95

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The theater club spends $1,197 for 63 student tickets.
Dmitriy789 [7]

Answer:

19 dollars per student

Step-by-step explanation:

4 0
3 years ago
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The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from
Vinvika [58]

Answer:

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

df=n_1 +n_2 -2=13+19-2=30  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

\bar X_{1}=810 represent the mean for sample 1  

\bar X_{2}=770 represent the mean for sample 2  

s_{1}=67 represent the sample standard deviation for 1  

s_{2}=56 represent the sample standard deviation for 2  

n_{1}=13 sample size for the group 2  

n_{2}=19 sample size for the group 2  

\alpha=0.05 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=13+19-2=30  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

4 0
3 years ago
A rucksack can hold a maximum of 6 kg.
ratelena [41]

Answer:

9 textbooks!

Step-by-step explanation:

Rucksack can hold = 6kg

Mass of textbook = 680g

So, here we need to show the division for finding the number of textbooks it can hold.

680 g in KG's = 0.68

Now, 6/0.68

That is 8.82 ( Round off = 9 textbooks)

5 0
3 years ago
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What is the monthly payment for a 10 year loan paid monthly for 10 years where the amount of the loan is $80,000 and the annual
Luden [163]

Answer:

0.004375%

Step-by-step explanation:

3.5

80000

x 100% = 0.004375% I hope this helps, I have the same mat

6 0
3 years ago
5(x + 9) = 5x + 45?<br> What property is this equation?
posledela

Answer:

distributive property

8 0
3 years ago
Read 2 more answers
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