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3 years ago

LPG is a better domestic fuel than wood?

Physics

1 answer:

Liula [17]3 years ago

4 0

Answer:

it is because it do not produce smoke like fuel from wood.

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The position of a charge an electric field that gives an electric ____ energy

11Alexandr11 [23.1K]

Answer:

The electric field at the location of the point charge is defined as the force F divided by the charge q: Figure 23.1. Electric force between two electric charges. The definition of the electric field shows that the electric field is a vector field: the electric field at each point has a magnitude and a direction.

4 0

3 years ago

A softball of mass 0.220 kg that is moving with a speed of 5.5 m/s (in the positive direction) collides head-on and elastically

Elanso [62]

Answer:

The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

Explanation:

Given that,

Mass of softball = 0.220 kg

Speed = 5.5 m/s

(a). We need to calculate the velocity of the target ball

Using conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

$0.220\times5.5+m_{2}\times0=0.220\times(-3.9)+m_{2}v_{2}$

$1.21=-0.858+m_{2}v_{2}$

$m_{2}v_{2}=2.068$ ....(I)

The velocity approach is equal to the separation of velocity

$u_{1}-u_{2}=v_{2}-v_{1}$

$5.5-0=v_{2}-(-3.9)$

$v_{2}=1.6\ m/s$

(b). We need to calculate the mass of the target ball

Now, Put the value of v₂ in equation (I)

$m_{2}\times1.6=2.068$

$m_{2}=\dfrac{2.068}{1.6}$

$m_{2}=1.29\ kg$

Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

3 0

3 years ago

Which of the following is true regarding momentum?

kakasveta [241]

Increasing the mass of an object increases its momentum.

Explanation:

Momentum of an object is measured as the quantity of motion done by the object.
It is calculated using the formula, p = m × v where m is mass of the object and v is the velocity of the object.
As momentum and mass vary proportionally, as seen in the formula, increasing the mass of an object will also increase its momentum.

8 0

3 years ago

A person hits a tennis ball with a mass of 0.058 kg against a wall.

horrorfan [7]

Explanation:

Mass of the ball, m = 0.058 kg

Initial speed of the ball, u = 11 m/s

Final speed of the ball, v = -11 m/s (negative as it rebounds)

Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

$F=\dfrac{m(v-u)}{t}$

$F=\dfrac{0.058\times (11-(-11))}{2.1}$

F = 0.607 N

(b) Area of wall, $A=3\ m^2$

Let P is the average pressure on that area. It is given by :

$P=\dfrac{F}{A}$

$P=\dfrac{0.607\ N}{3\ m^2}$

P = 0.202 Pa

Hence, this is the required solution.

8 0

3 years ago

A brick is released with no initial speed from the roof of a building and strikes the ground in 1.80 s , encountering no appreci

Mars2501 [29]

<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent. vi = 0 vf = x d = ? d = vi + 1/2 a t^2 d = 0 + 1/2 (9.8) (1.8)^2 d = 15.9 m (counting sig figs)</span>

8 0

4 years ago

LPG is a better domestic fuel than wood?​

LPG is a better domestic fuel than wood?