Refrigerant entering the compressor of a refrigeration system is sub-cooled liquid
The liquid refrigerant is sub-cooled to ensure that only liquid and not the vapour enters the throttling valve. In a refrigeration system, the superheating decreases COP increase refrigerating effect but increasing amount of work done. The coefficient of performance or COP (sometimes CP or CoP) of a heat pump, refrigerator or air conditioning system is a ratio of useful heating or cooling provided to work (energy) required. Higher COPs equate to higher efficiency, lower energy (power) consumption and thus lower operating costs.
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Answer:
intensity of the light that emerges from the three filters is 560.80 W/m²
Explanation:
Given data
intensity I = 1375 W/m2
angle 1 = 31.0°
angle 2 = 41.0°
to find out
intensity of the light that emerges from the three filters
solution
we know intensity of light pass 1st polarize = I/2 = 1375 / 2 = 687.5 W/m2
so intensity after 2nd polarize pass = I 1st cos²(θ)
I 2nd = 687.5 cos²(31) = 687.5 ( 0.836754) = 575.27 W/m2
and
intensity after 3rd polarize pass = I 2nd cos²(θ)
I 3rd = 575.27 cos²(41) = 575.27 (0.974839) = 560.80 W/m2
so that intensity of the light that emerges from the three filters is 560.80 W/m²
Answer:
acc to formula= F= G m1m2/rsq
mass of Uranus= F×r sq/G×m
M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21
=3×10^25-8×7614×7614/667×301×10^-2-11+21-2
=173918988×10^11/200767
=866×10^11(approx)
Answer:
r = 0.405m = 40.5cm
Explanation:
In order to calculate the length of the string between Wanda and the ball, you take into account that the tension force is equal to the centripetal force over the ball. So, you can use the following formula:
(1)
Fc: centripetal acceleration (tension force on the string) = 12N
m: mass of the ball = 60g = 0.06kg
r: length of the string = ?
v: linear speed of the ball = 9.0m/s
You solve for r in the equation (1) and replace the values of the other parameters:
The length of the string between Wanda and the ball is 0.405m = 40.5cm
Answer:
surface temperature of the chip located 120 mm Ts=42.5°C
surface temperature of the chip in Mexico Ts=46.9°C
Explanation:
from the energy balance equation we have to:
q=E=30W
from Newton´s law:
Ts=Tα+(q/(h*A)), where A=l^2
N=h/k=0.04*(Vl/V)^0.85*Pr^1/3
data given:
l=0.12 m
v=10 m/s
k=0.0269 W/(m*K)
Pr=0.703
Replacing:
h=0.04*(0.0269/0.12)*(10*0.12)/((16*69x10^-6))^0.85*(0.703^1/3) = 107 W/m^2*K
The surface temperature at sea level is equal to:
Ts=25+(30x10^-3/107*0.004^2)=42.5°C
h=0.04*(0.0269/0.12)*((10*0.12)/(21*81x10^-6))^0.85*(0.705^1/3)=85.32 W/(m*K)
the surface temperature at Mexico City is equal to:
Ts=25+(30x10^-3/85.32*0.004^2)=46.9°C
