Answer:
NO = 0.0265 mol
Br₂ = 0.0133 mol
NOBr = 0.0389 mol
Explanation:
Let's consider the following reaction.
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
We can find the composition at equilibrium using an ICE chart. Let x be an unknow amount.
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
I 0.0655 0.0328 0
C -2x -x +2x
E 0.0655 - 2x 0.0328 - x 2x
At equilibrium, the mixture contains 0.0389 mol NOBr. Then,
0.0389 mol = 2x
x = 0.0195 mol
The composition of the equilibrium mixture is:
NO = 0.0655 - 2x = 0.0265 mol
Br₂ = 0.0328 - x = 0.0133 mol
NOBr = 0.0389 mol
1. put goggles on
2.but gloves on
3.put a lab coat on
Answer:
2.088464 grams.
Explanation:
The density of neon is 0.9002 g/L. Multiplying this value by the number of liters gives how many grams of neon it contains.
0.9002(2.32) = 2.088464
- When you are sitting constant at bench your blood vessels and pressure of muscles are stable there.
- When you sudden wake up blood also wakes up .
- The gravity pulls it down from head.
- So you feel lightweight.
Muscular and nervous system involved
Answer:
See explanation below.
Explanation:
We can obtain the Gibb's free energy from the formula;
∆G= ∆H - T∆S
Where;
∆G = change in free energy= the unknown
∆H= change in enthalpy = 3352 kJ
∆S= change in entropy of the solution= 625.1 J/K
T= absolute temperature = 298 K
Substituting values;
∆G= 3352 ×10^3 J - (298 K × 625.1 J/K)
∆G= 3352 ×10^3 J - 186279.8
∆G= 3.16 × 10^6 J
At 5975K,
∆G= ∆H - T∆S
∆G= 3352 ×10^3 J - (5975K × 625.1 J/K)
∆G= 3.352 ×10^6 J - 3.735 × 10^6
∆G= -3.83×10^5 J
At equilibrium, ∆G=0, Teq is given by;
0= 3352 ×10^3 J - (Teq × 625.1 J/K)
0= 3352 ×10^3 - 625.1Teq
625.1Teq = 3352 ×10^3
Teq= 3352 ×10^3/625.1
Teq= 5362.3 K