Answer:
43.75 ml
Explanation:
Given that the equation of the reaction is;
2HNO3(aq) + Ca(OH)2(aq) ---> Ca(NO3)2(aq) + 2 H20(l)
Concentration of acid CA= 0.05 M
Concentration of base CB = 0.02 M
Volume of acid VA = 35.00ml
Volume of base VB= ???
Number of moles of acid NA= 2
Number of moles of base NB=1
From
CAVA/CBVB= NA/NB
Making VB the subject of the formula;
VB= CAVANB/CBNA
VB= 0.05 × 35 × 1/ 0.02 × 2
VB=1.75 /0.04
VB= 43.75 ml
Rock a is a sedimentary and rock B is a sediment rock also known as sandstone
Answer:
Mass of CaCO₃ decomposed = 25 g
Explanation:
Given data:
Mass of CaCO₃ decomposed = ?
Mass of CaO produced = 14 g
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of CaO:
Number of moles = mass/molar mass
Number of moles = 14 g/ 56 g/mol
Number of moles =0.25 mol
Now we will compare the moles of CaO with CaCO₃.
CaO : CaCO₃
1 : 1
0.25 : 0.25
Mass of CaCO₃:
Mass = number of moles × molar mass
Mass = 0.25 mol × 100 g/mol
Mass = 25 g
Answer: The empirical formula is 
.
Explanation:
Mass of C = 1.71 g
Mass of H = 0.287 g
Step 1 : convert given masses into moles.
Moles of C = 
Moles of H = 
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
The ratio of C: H = 1: 2
Hence the empirical formula is .
Answer:
Because energy is conserved, the kinetic energy of a block at the bottom of a frictionless
ramp is equal to the gravitational potential energy of the block at the top of the ramp. This
value is proportional to the square of the block’s velocity at the bottom of the ramp.
Therefore, the block’s final velocity depends on the height of the ramp but not the steepness
of the ramp
Explanation:
