Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C
A linear equation is a straight line. The equation is of the type y = MX + N
The soluction of that system is Ax^2 + Bx + C = MX + N
=> Ax^2 + (B-M)x + (C-N) = 0
That is a quadratic equation.
A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.
So you must select 0, 1 and 2.
You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.
You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.
Answer:
Step-by-step explanation:
Given
See attachment for grid
Required
Find c and d
From the attachment, we have:
--- Point on A
--- Corresponding point on B
When A is reflected across the x-axis, the rule is:
So, we have:
Next, is to calculate the translation from 
to 
This is calculated using:
and
So, we have:
---- i.e. Shift by 6 units to the left
--- i.e. Shift by 1 unit down
The professional runner can run 4 1/6 miles in 30 minutes.
Since the professional can run 1 1/4 times as far in 30 minutes, we multiply 3 1/3 by 1 1/4:
(3 1/3)(1 1/4)
Convert each to an improper fraction (multiply the whole number by the denominator and add the numerator):
10/3(5/4) = 50/12 = 25/6 = 4 1/6.
The vertex is halfway between 700 and 800, and the x value of the vertex is right over the 10. So since the x value represents dollars, the maximum (vertex) is 10$ each for 750$
Answer:
d) none of these lines fit the data
