Answer:
68% of jazz CDs play between 45 and 59 minutes.
Step-by-step explanation:
<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?
Let X = <u>playing time of jazz CDs</u>
SO, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
Now, according to the 68-95-99.7 rule, it is stated that;
- 68% of the data values lie within one standard deviation points from the mean.
- 95% of the data values lie within two standard deviation points from the mean.
- 99.7% of the data values lie within three standard deviation points from the mean.
Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;
For 45 minutes, z-score is =
= -1
For 59 minutes, z-score is =
= 1
This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.
Answer:
There are two solutions to this problem.
x=4
or
x=-4
Step-by-step explanation:
Answer:
125°
Step-by-step explanation:
x + 24 is equal to 1.
6 is equal to 4x + 1
1 and 4x + 1 = 180°
x + 24 + 4x + 1 = 180
4x + x + 24 + 1 = 180
5x + 25 = 180
5x = 180 - 25
5x = 155
5x/5 = 155/5
x = 31
(angle) 6 = 4x + 1
(angle) 6 = 4(31) + 1
(angle) 6 = 124 + 1
(angle) 6 = 125°
Answer:
Answer Counterclockwise rotation about the origin by 180 degrees followed by reflection about the y-axis explanation the given figure has vertices p(1,2),q(2,1),r(3,2),s(3,3)recall that for counterclockwise rotation about the origin, (x,y)\rightarrow (-x,-y)when we rotate figure pqrs counterclockwise through an angle of 180° about the origin, the coordinates will become p1( - 1, - 2),q1( - 2, - 1),r1( - 3, - 2),s1( - 3, - 3)next, we reflect in the y-axis by negating the x-coordinates of the resulting figure to obtain,p'(1, - 2),q'(2, - 1),r'(3, - 2),s'(3, - 3)
Step-by-step explanation:
Answer:
Let x = number of regular tickets sold.
Let y represent the number of student tickets sold.
12x+8y≤100012x+8y≤1000
x+y≥200x+y≥200
12x+8y≤20012x+8y≤200
x+y≤200x+y≤200
12x+8y≥1000
hope this helps
Step-by-step explanation: